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3 years ago

Generate an equivalent expression using the distributive property 3(6 - 7a) A.18+21a B.9+10a C.9+10a D.18-21a

Mathematics

2 answers:

loris [4]3 years ago

8 0

Answer:

3(6-7a)

18-21a

a and d

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

Step-by-step explanation:

When doing distributive property, you have to multiply the outside number by all of the inside numbers

so 3(6 - 7a), you would have to do 3*6 and 3*-7a and then you would add those two values:

So in this case, you would do 18 + (-21a) which is just 18 - 21a.

Just to help you visualize distributive property better

3(6+8) = 3*6 + 3*8

4(20+5+3) = 4*20 + 4*5 + 4*3

10(15.5 - 24.4 + 23.21) = 10*15.5 + 10*(-24.4) + 10*23.21

I hope this helped, let me know if you have any questions

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The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

5 0

3 years ago

Urgent, please i will give brainliest

Ne4ueva [31]

Answer:

1. $\frac{\sqrt{13} }{3}$

2. 3.2362

3. $\frac{60}{11}$

Step-by-step explanation:

Cot is the trigonometric ratio defined by "adjacent" over "opposite". So, adjacent = 2 and opposite = 3.

By pythagorean theorem, we have the "hypotenuse" as $\sqrt{2^2+3^2}=\sqrt{13}$

Csc is defined as the trig ratio "hypotenuse" over "opposite". We know the sides, so Csc $\theta$ = $\frac{\sqrt{13} }{3}$

First answer choice is right.

By definition, Csc $\theta$ is the inverse of Sine $\theta$ . If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:

$Csc\theta=\frac{1}{0.3090}\\=3.2362$

Third answer choice is right.

By definition tan and cot are inverse of each other. So the value of tan is the reciprocal of the value of cot. We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

$Cot\theta=\frac{60}{11}$

Third answer is right.

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to the expression below?

Mama L [17]

Answer:

5r + 2p + 6

Step-by-step explanation:

= 4r + 9 + r + 2p - 3

= 4r + r + 2p + 9 - 3

= 5r + 2p + 6

4 0

3 years ago

Point A is located at (−5, 2) on a coordinate grid. Point A is translated 4 units to the right and 2 units down to create point

love history [14]

Answer:C) 4.5 units

Step-by-step explanation:

4 0

3 years ago

Write a polynomial in standard form with the zeros –4 0 1 and 4

Tasya [4]

Step-by-step explanation:

Hi there!

Zero of the polynomial is the value of "X" that gives final answer as zero.

So, as the polynomial in the second gives zero every time when we keep the zero which are given in the question. It is the answer.

Check:

• x⁴ - x³ - 16x² + 16x

(-4)

Keep the value -4 as the value of X in polynomial.

= (-4)⁴-(-4)³ -16*(-4)²+16*(-4)

= 256+64-256-64

= 0

Keep the value 0 as the value of X in polynomial.

= (0)⁴-(0)³ -16*(0)²+16*(0)

= 0-0-0+0

= 0

Keep the value 1 as the value of X in polynomial.

= (1)⁴-(1)³ -16*(1)²+16*(1)

= 1-1-16+16

= 0

Keep the value 4 as the value of X in polynomial.

= (4)⁴-(4)³ -16*(4)²+16*(4)

= 256 - 64-256+64

= 0

Therefore, the correct answer is option B.

Hope it helps!

6 0

3 years ago