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3 years ago

Generate an equivalent expression using the distributive property 3(6 - 7a) A.18+21a B.9+10a C.9+10a D.18-21a

Mathematics

2 answers:

loris [4]3 years ago

8 0

Answer:

3(6-7a)

18-21a

a and d

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

Step-by-step explanation:

When doing distributive property, you have to multiply the outside number by all of the inside numbers

so 3(6 - 7a), you would have to do 3*6 and 3*-7a and then you would add those two values:

So in this case, you would do 18 + (-21a) which is just 18 - 21a.

Just to help you visualize distributive property better

3(6+8) = 3*6 + 3*8

4(20+5+3) = 4*20 + 4*5 + 4*3

10(15.5 - 24.4 + 23.21) = 10*15.5 + 10*(-24.4) + 10*23.21

I hope this helped, let me know if you have any questions

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What is the value of x in the equation 4x+8y=40 when y=0.8

GREYUIT [131]

Substitute in 0.8 for y.

$4x+8y=40 \\ \\ 4x + 8(0.8) = 40 \\ \\ 4x + 6.5 = 40 \\ \\ 4x = 40 - 6.4 \\ \\ 4x = 33.6 \\ \\ x = 8.4 \\ \\$

The final result is: x = 8.4.

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3 years ago

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The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3

RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that $p = 0.1$

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243$

There is a 24.3% probability that one of the calculators will be defective.

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3 years ago

Mitch is buying candy bars for his friends. He wants to give 2 bars to each friend, and he wants to have 10 spare. He can afford

Xelga [282]

Hi!

So we know that he has 20 candy bars.

= 20

He wants to give 2 to each friend. So 2 candy bars x friends.

He's going to keep 10.

+10

Put all of the parts together.

2f + 10 = 20

The answer is 2f + 10 = 20

Hope this helps!

-Peredhel

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3 years ago

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A 2-quart carton of apple juice costs $4.56. What is the price per cup?

Ede4ka [16]

Answer:

57 cents

$0.57

Step-by-step explanation:

1 quart= 4 cups

2 quarts=8 cups

8 cups=4.56

Divide each side by 8

1 cup=0.57

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3 years ago

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Alenkasestr [34]

Answer:

There are two inequalities that represent the total number of

balloons, b, they can purchase and not spend over their budgeted amount:

0.65b ≤ 70

0.65b + 225 ≤ 295

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Budget to plan the event = $ 295

Expenses on supplies so far = $ 225

Cost of each balloon = $ 0.65

2. Which of the following inequalities represents the total number of

balloons, b, they can purchase and not spend over their budgeted amount?

1. Let's find how much of the budget is still available:

Budget available = Budget to plan the event - Expenses on supplies so far

Budget available = 295 - 225

Budget available = $ 70

2. Let's find the inequality that represents the total number of

balloons, b, they can purchase and not spend over their budgeted amount.

Number of balloons ≤ Budget available/Cost of each balloon

Replacing with the values we know, we have:

b ≤ 70/0.65

0.65b ≤ 70

or we can write it also including the total budget this way:

Number of balloons ≤ Budget to plan the event - Expenses on supplies so far /Cost of each balloon

Replacing with the values we know, we have:

b ≤ (295 - 225)/0.65

0.65b ≤ 295 - 225

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3 years ago