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3 years ago

Generate an equivalent expression using the distributive property 3(6 - 7a) A.18+21a B.9+10a C.9+10a D.18-21a

Mathematics

2 answers:

loris [4]3 years ago

8 0

Answer:

3(6-7a)

18-21a

a and d

Step-by-step explanation:

SVETLANKA909090 [29]3 years ago

6 0

Answer:

Step-by-step explanation:

When doing distributive property, you have to multiply the outside number by all of the inside numbers

so 3(6 - 7a), you would have to do 3*6 and 3*-7a and then you would add those two values:

So in this case, you would do 18 + (-21a) which is just 18 - 21a.

Just to help you visualize distributive property better

3(6+8) = 3*6 + 3*8

4(20+5+3) = 4*20 + 4*5 + 4*3

10(15.5 - 24.4 + 23.21) = 10*15.5 + 10*(-24.4) + 10*23.21

I hope this helped, let me know if you have any questions

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At a movie theater, the price of 2 adult tickets and 4 child tickets is $48. The price of 5 adult tickets and 2 child tickets is

Setler [38]

Answer:

adult=10

Child=7

One adult and one child=10+7=17

Step-by-step explanation:

Let a be the price of an adult ticket

c = price of the child ticket

2a+4c = 48

5a+2c = 64

Multiply the second equation by -2 and add to the first equation

2a+4c = 48

-10a-4c = -128

---------------------

-8a +0c = -80

Divide by -8

-8a/-8 = -80/-8

a = 10

Now find c

2a+4c=48

2(10)+4c=48

20+4c=48

4c=48-20

4c=28

4c/4=28/4

c=7

6 0

2 years ago

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A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba

mariarad [96]

There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
$(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120$
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
$(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15$
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
$P=\frac{60}{120}=\frac{1}{2}=50\%$

The probability is 1/2, or 50%.

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3 years ago

Find the gcf and lcm of 20x^2y^3 60x^3y^2| 40xy^2

LenaWriter [7]

Gcf is the grouping of all the factors common to both groups
lcm is a group of all the factors that has all the elements of both groups

factor
20x^2y^3=2*2*5*x*x*y*y*y
60x^3y^2=2*2*3*5*x*x*x*y*y
40xy^2=2*2*2*5*x*y*y

the GCF=2*2*5*x*y*y=20xy^2
the LCM=2*2*2*3*5*x*x*x*y*y*y=120x^3y^3

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3 years ago

Two equations are shown:

Aneli [31]

Equation A is linear and equation B is nonlinear

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3 years ago

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What is the solution for the equation 8x − 12 = 4x? x = ___. (Input whole number only).

seropon [69]

8x - 12 = 4x
8x - 4x = 12
4x = 12
x = 12/4
x = 3

8 0

2 years ago