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Delicious77 [7]
3 years ago
10

What is the concentration of H+ ions at a pH = 7? mol/L What is the concentration of OH– ions at a pH = 7? mol/L What is the rat

io of H+ ions to OH– ions at a pH = 7? :1
Physics
2 answers:
AnnZ [28]3 years ago
8 0
<h3><u>Answer;</u></h3>

= 0.0000001 mol/L  

= 0.0000001 mol/L  

= 1:1

<h3><u>Explanation;</u></h3>

What is the concentration of H+ ions at a pH = 7?

The formula for ph is given by:

pH=−log10[H+]

In calculating for the concentration of hydrogen ion, the formula is given by:

[H+]=(10)^(-pH)

Therefore; at pH = 7

[H+]=(10)^(-7)

<u>= 0.0000001 mol/L </u> 

What is the concentration of OH– ions at a pH = 7?

pH+pOH=14

7+pOH=14

pOH= 7

[OH-]=(10)^(-pOH)

[OH-]=(10)^(-7)

<u>= 0.0000001 mol/L  </u>

What is the ratio of H+ ions to OH– ions at a pH = 7?  

1:1

LuckyWell [14K]3 years ago
3 0

Answer: The answer is  

=0.0000001

=0.0000001

=1

Explanation: hope this is helpful :)

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The metal cases of electrical appliances are connected to an earth wire.Which statement is not correct?A The live wire may becom
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Given that metal cases of electrical appliances are connected to the wire, let's select the statement which is not correct from the list of statements.

The earth wire is used to protect you and help reduce the risk of receiving an electric shock. The earth wire reduces the risk of electric shock by creating a path for a fault or lose current to flow to the Earth.

The Live wire may become loose and touch the metal case. In this case, the earth wire will channel the fault current to the earth thereby reducing the risk of electric shock.

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n the Bohr model of the hydrogen atom (see Section 39.3), in the lowest energy state the electron orbits the proton at a speed o
Ivahew [28]

Answer:

(a) T=1.5*10^{-6}s

(b) I=1.1*10^{-3}A

(c) \mu=9.71*10^{-24}A\cdot m^2

Explanation:

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T=\frac{2\pi r}{v}\\T=\frac{2\pi(5.3*10^{-11}m)}{2.2*10^{6}\frac{m}{s}}\\T=1.5*10^{-6}s

(b) Current means charge over time, So, in this case is charge over period:

I=\frac{q}{t}\\I=\frac{e}{T}\\I=\frac{1.6*10^{-19}C}{1.5*10^{-6}s}\\\\I=1.1*10^{-3}A

(c) Magnetic moment is given by:

\mu=IA

Here A is the area of the orbit.

\mu=I\pi r^2\\\mu=(1.1*10^{-3}A)\pi(5.3*10^{-11}m)^2\\\mu=9.71*10^{-24}A\cdot m^2

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