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kaheart [24]
3 years ago
9

In a game of baseball, a player hits a high fly ball to the outfield. (a) Is there a point during the flight of the ball where i

ts velocity is parallel to its acceleration? (b) Is there a point where the ball’s velocity is perpendicular to its acceleration? Explain in each case.
Physics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

a) No

b) No

Explanation:

When a bat is hit in a game of baseball such that it flies out of the field that means it is going with some angle to the horizontal.

a)

Then is such a case the velocity of the ball is never parallel to the acceleration because there acts a net acceleration which is resultant of the acceleration due to the applied force and the acceleration due to gravity but a component of the velocity when the ball descends the height acts parallel to the gravity.

b)

At no point during the motion of the ball its velocity is perpendicular to its acceleration because it has an initial angle of projection form the horizontal.

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3 0
3 years ago
A 82-kg fisherman in a 112-kg boat throws a package of mass m = 15 kg horizontally toward the right with a speed of vi = 4.8 m/s
abruzzese [7]

Answer:

0.37 m/s to the left

Explanation:

Momentum is conserved.  Initial momentum = final momentum.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Initially, both the fisherman/boat and the package are at rest.

0 = m₁ v₁ + m₂ v₂

Plugging in values and solving:

0 = (82 kg + 112 kg) v + (15 kg) (4.8 m/s)

v = -0.37 m/s

The boat's velocity is 0.37 m/s to the left.

8 0
3 years ago
Ball A is allowed to fall and strike ball B. Assume that all of ball A's energy is transferred to ball B at point I, and that th
Alika [10]

Answer:

Explanation:

If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B

Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A

K. E = T. E - P.E

5 0
4 years ago
Read 2 more answers
What is your initial speed if you accelerate at 5.8 m/s/s for 3.0 seconds and achieve a final speed of 45 m/s?
Natali5045456 [20]

Answer:

27.6 m/s

Explanation:

hopefully it makes sense and is visible

:)

8 0
3 years ago
The gravitational force of attraction between two students sitting at their desks in physics class is 2.59 × 10−8 N. If one stud
motikmotik
<h2>The distance between students is 2.46 m</h2>

Explanation:

The force of attraction due to Newton's gravitation law is

F = \frac{Gm_1m_2}{r^2}

Here G is the gravitational constant

m₁ is the mass of one student

m₂ is the mass of second student .

and r is the distance between them

Thus r = \sqrt{\frac{Gm_1m_2}{F} }

If we substitute the values in the above equation

r = \sqrt{\frac{6.673x10^-^1^1x31.9x30.0}{2.59x10^-^8} }

= 2.46 m

3 0
3 years ago
Read 2 more answers
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