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Alisiya [41]
3 years ago
13

A garden has a length of 9 1/6 feet and a width of 6 3/4 feet. what is the area

Mathematics
1 answer:
givi [52]3 years ago
7 0

Answer:

Can i have ur mail

Step-by-step explanation:

Come back friend

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Which scatter plots shows a nonlinear association
aliya0001 [1]

Answer:

Graph B.

Step-by-step explanation:

this is nonlinear because you cannot connect or create a line with where the dots are plotted if that makes sense.

hope this helps!

8 0
3 years ago
1) Which relation is a function?
jasenka [17]

Answer:

B

Step-by-step explanation:

x = y-4x^2 can be rearranged to get y = 4x^2 + x, which is a function

3 0
2 years ago
1/4 times X -1+ 3X equals 2
iris [78.8K]

Answer:

41

Step-by-step explanation:

4 0
3 years ago
The graph of g(x) is a transformation of the graph of f(x)=2x. Enter the equation for g(x) in the box. g(x) =
Lunna [17]
<h3>Answer:  g(x) = 2^x - 3</h3>

The -3 is not in the exponent

Explanation:

The parent function is f(x) = 2^x. Plugging in x = 0 leads to y = 1. So the point (0,1) is on the f(x) curve. Going from (0,1) to (0,-2) is a vertical shift of 3 units downward. To represent this shift, we tack on a "-3" at the end of the f(x) function.

g(x) = f(x) - 3\\\\g(x) = 2^x - 3

You could look at other points as well, but I find working with x = 0 is easiest.

As a check, plugging x = 0 into g(x) leads to...

g(x) = 2^x - 3\\\\g(0) = 2^0 - 3\\\\g(0) = 1 - 3\\\\g(0) = -2

This confirms our answer.

4 0
3 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

8 0
3 years ago
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