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sladkih [1.3K]
3 years ago
13

Simply the imaginary number square root -45

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Answer:

3i\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-45}

= \sqrt{9(5)(-1)}

= \sqrt{9} × \sqrt{5} × \sqrt{-1}

= 3 × \sqrt{5} × i

= 3i\sqrt{5}

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<h3>Answer:</h3>
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The last number, at lower right, is the "remainder", also the value of f(x). Here, it is 2 (not 0) for x=1, so f(1) = 2.

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ANSWER:

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Unfortunately, you haven't provided enough info.  Could you possibly attach a sketch or photo image of this problem?  What do you mean by 8_7?  

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