A triangle has two sides of length 4 and 10. What is the smallest possible whole-number length for the third side?

Find the circumference of a circle with radius, r = 11.5m. Give your answer in terms of π .

nignag [31]

Answer:

So,

if C = 2πR

you take 2π you get 6.28

so C=6.28 x r

the radius is 11.5 so

6.28 x 11.5 = 72.2566

the circumference is 72.2566

Step-by-step explanation:

4 0

2 years ago

The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.

Leni [432]

1 foot = 12 inches. If you multiply 12 by 12 and then add 5, you get 149. 149 is less than 162 so it will be able to fit!

8 0

2 years ago

ANSWER ASAP

xz_007 [3.2K]

Answer:

12.5 pi or 39.26990

Step-by-step explanation:

First we can find the radius, which is half the diameter, 5 feet. To find the area of a semi-circle we would find the area of the circle and then divide by 2:

$\frac{\pi r^2}{2}$

We can substitute what we have:

$\frac{25\pi }{2}$

This gives us:

12.5 pi or 39.26990(Not sure what format you need it in)

6 0

2 years ago

Becky is 18 and would like to buy a house when she is 36. What is the discount factor for today's prices if the housing values i

statuscvo [17]

you need to find the amount of years between now and when she wants to buy a home. 36-18= 18. then you take 18 and multiply is by %6. 18x%6 or 18x.06 =108% or 1.08.

The discount prices for today's housing values compared to 18 years from now with a 6% increase per year would be 108% discount.

3 0

2 years ago

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{270.5 - 255}{6.185}$

$Z = 2.51$

$Z = 2.51$ has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at brainly.com/question/24261244

8 0

2 years ago