Answer:
So,
if C = 2πR
you take 2π you get 6.28
so C=6.28 x r
the radius is 11.5 so
6.28 x 11.5 = 72.2566
the circumference is 72.2566
Step-by-step explanation:
1 foot = 12 inches. If you multiply 12 by 12 and then add 5, you get 149. 149 is less than 162 so it will be able to fit!
Answer:
12.5 pi or 39.26990
Step-by-step explanation:
First we can find the radius, which is half the diameter, 5 feet. To find the area of a semi-circle we would find the area of the circle and then divide by 2:

We can substitute what we have:

This gives us:
12.5 pi or 39.26990(Not sure what format you need it in)
<span>you need to find the amount of years between now and when she wants to buy a home. 36-18= 18. then you take 18 and multiply is by %6. 18x%6 or 18x.06 =108% or 1.08.
The discount prices for today's housing values compared to 18 years from now with a 6% increase per year would be 108% discount. </span>
Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with
.
In this problem:
- 15% do not show up, so 100 - 15 = 85% show up, which means that
. - 300 tickets are sold, hence
.
The mean and the standard deviation are given by:


The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is
, which is the <u>p-value of Z when X = 270.5</u>.



has a p-value of 0.994.
0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
A similar problem is given at brainly.com/question/24261244