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madam [21]
2 years ago
10

A triangle has two sides of length 4 and 10. What is the smallest possible whole-number length for the third side?

Mathematics
1 answer:
mars1129 [50]2 years ago
8 0

Answer:

I think it's 4×10=40

Answer =40

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Sorry for the crumbled paper Can someone help me<br><br> Complete the chart
Verizon [17]

Answer:

4/10, 0.4, 40%

1/4, 0.25, 25%

Hope this helps also "Hi" again. :)

5 0
3 years ago
Someone plz. help me with 7 and 8
Anon25 [30]
7.) the equation of the circle is
(x - 3)^2 + (y - 4)^2 = 25

If you substitute the point in you get
(6-3)^2 + (8-4)^2 = 25
3^2 + 4^2 = 25
9 + 16 = 25
25 = 25

Both sides of the equation are the same so it proves it lies on the circle

8.) you add the x coordinates together and divide by 2
7 + 4 = 11
11/2 = 5.5
You use +7 because you need to find the midpoint.
You then add 5.5 to - 7 or - 5.5 from 4
-7 + 5.5 = - 1.5

You do the same for y coordinates
6+5 = 11
11/2 = 5.5
6-5.5 = 0.5

So the coordinates of Rachel's house are
(-1.5, 0.5)
3 0
3 years ago
Translate the shape by the vector -1 5​
Juliette [100K]

Answer:

la forma por el vector -1 5

Step-by-step explanation:

8 0
2 years ago
ABCD is a kite.
stepan [7]

Answer:

wouldn't it be 40 if the opposite side is 40 ?

3 0
3 years ago
Read 2 more answers
What is the quadratic portion in this quadratic equation 7x2-12x+16=0
alexdok [17]

Answer:

x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

Step-by-step explanation:

Solve for x:

7 x^2 - 12 x + 16 = 0

Hint: | Write the quadratic equation in standard form.

Divide both sides by 7:

x^2 - (12 x)/7 + 16/7 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 16/7 from both sides:

x^2 - (12 x)/7 = -16/7

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36/49 to both sides:

x^2 - (12 x)/7 + 36/49 = -76/49

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6/7)^2 = -76/49

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6/7 = (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the first equation: Solve for x.

Add 6/7 to both sides:

x = 6/7 + (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the second equation: Solve for x.

Add 6/7 to both sides:

Answer:  x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

6 0
3 years ago
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