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2 years ago

How do you calculate the common difference?

Mathematics

1 answer:

SCORPION-xisa [38]2 years ago

7 0

Answer:

<h3> second term minus first term </h3>

Step-by-step explanation:

Difference is a result of subtracting (not dividing!)

To calculate difference between two terms we have to subtract the previous from the next:

$d=a_2-a_1=a_3-a_2=a_4-a_3=...=a_n-a_{n-1}$

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What is 2 + 100000+50000

xxMikexx [17]

Answer:

150002

Step-by-step explanation:

2+100000+50000

Add 2 and 100000 to get 100002.

100002+50000

Add 100002 and 50000 to get 150002.

150002

8 0

2 years ago

Read 2 more answers

Ax+by=(a-b) , bx - ay =(a+b) simultaneous linear equations using cross multiplication

Molodets [167]

Answer:

$x=1\,,\,y=-1$

Step-by-step explanation:

Given: $ax+by=a-b\,,\,bx-ay=a+b$

To solve: the given linear equations

Solution:

Consider the equations:

$A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0$

By method of cross multiplication:

$\frac{x}{B_1C_2-B_2C_1}=\frac{y}{C_1A_2-C_2A_1}=\frac{1}{A_1B_2-A_2B_1}$

For equations: $ax+by=a-b\,,\,bx-ay=a+b$

$ax+by-(a-b)=0\\bx-ay-(a+b)=0$

Take $A_1=a\,,\,B_1=b\,,\,C_1=-(a-b)\,,\,A_2=b\,,\,B_2=-a\,,\,C_2=-(a+b)$

So,

$\frac{x}{-b(a+b)-a(a-b)}=\frac{y}{-b(a-b)+a(a+b)}=\frac{1}{-a^2-b^2}\\\frac{x}{-ab-b^2-a^2+ab}=\frac{y}{-ab+b^2+a^2+ab}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\\frac{x}{-(a^2+b^2)}=\frac{1}{-(a^2+b^2)}\,,\,\frac{y}{a^2+b^2}=\frac{1}{-(a^2+b^2)}\\x=1\,,\,y=-1$

6 0

3 years ago

If each letter of the alphabet is worth two more than its preceding letter, where A is the first number and equals 1, B is the s

andrey2020 [161]

Answer:

<h2>The total value of all the letters in the alphabet is 676.</h2>

Step-by-step explanation:

The problem is about an arithmetic sequence where the difference is 2, the first term is 1 and we know that the alphabet has 26 letters.

To find the total sum of all values, we have to use the following formula

$S_{n}=\frac{n}{2}(2a_{1}+(n-1)d )$

Where $n=26$ , $a_{1}=1$ and $d=2$ . Replacing values, we have

$S_{26}=\frac{26}{2}(2(1)+(26-1)2) =13(2+50)=13(52)=676$

Therefore, the total value of all the letters in the alphabet is 676.

7 0

3 years ago

Read 2 more answers

Find the area of the triangle belowunits given are cm, cm^2, cm^3

zloy xaker [14]

Answer:

$A_T=150cm^2$

Explanation: We need to find the area of the triangle, We know that the area of any right triangle is:

$A_T=\frac{1}{2}(b\times h)$

Therefore in the information given we have the following:

$\begin{gathered} h=20\operatorname{cm} \\ b=15\operatorname{cm} \end{gathered}$

Therefore the Area of this triangle is as follows:

$\begin{gathered} A_T=\frac{1}{2}(b\times h) \\ \therefore\rightarrow \\ A_T=\frac{1}{2}(20cm\times15cm)=\frac{1}{2}(20\times15)cm^2 \\ A_T=\frac{1}{2}(300)cm^2=150cm^2 \\ \therefore\rightarrow \\ A_T=150cm^2 \end{gathered}$

Note! Units are centimeter-squared

4 0

1 year ago

Boy Scouts Popcorn Sales

Karolina [17]

Answer:

Step-by-step explanation:

5 plus 4 is nine.

I based everything on how much times more it was at first, and did that times 9 for every name.

I added up how much more boxes they got in total and got 60.

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2 years ago