Estimate the question 435 x 5.3

Daniel earns a commission of 3% on every home he sells. Recently, Daniel

Leokris [45]

Answer:

The answer in 180000 * 3 ÷ 100 = 5400$

7 0

3 years ago

Find the distance between the points (4,-2) and (0,10)

vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: $\sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}}$ We can now put in values and solve.

$\sqrt{(4-0)^{2} + (-2-10)^{2}}$

$\sqrt{16 + 144}$

$\sqrt{160}$

3 0

3 years ago

. What are the equation and slope of the line that is parallel to the y-axis and goes through the point (1,-2)?

Brrunno [24]

The answer:

x = 1

Explanation:

If the line is parallel to the y-axis it has no slope, so you would only write down the x-intercept.

8 0

2 years ago

I would like to buy a sandwich and pancakes, which would be $8.50, with a 6% tax and 20% gratuity, how much would that be all in

Luda [366]

Answer:

9.01 maybe my math might be wrong

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago