Estimate the question 435 x 5.3

Write an expression for the perimeter of the triangle shown in the picture

umka2103 [35]

Answer: x-5+5+5

Step-by-step explanation:

3 0

3 years ago

Rhonda took $20 with her to spend on popcorn and candy for herself and her friends at the movie theater. The price for each bag

MrRa [10]

The linear equation that represents the scenario is 5x + 2.5y = 20

<h3>How to determine the equation?</h3>

The given parameters are:

Popcorn = $5 per bag
Candy = $2.5 per bag i.e. half the price of pop corn

Let x represents popcorn and y represents candy.

So, we have:

5x + 2.5y = 20

The intercepts in this case are the maximum number of candy and popcorn Rhonda can buy

See attachment for the graph

Read more about linear functions at:

brainly.com/question/4025726

#SPJ1

5 0

2 years ago

A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon

melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.

X~ Uniform(0,100)

Then the probability mass function is given as follows.

$f(x) = P(X=x) = 1/100 \,\,\,\, \text{if} \,\,\,\, 0 \leq x \leq 100\\f(x) = P(X=x) = 0 \,\,\,\, \text{otherwise}$

Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located 70 meters away from city A then the mid point between 20 and 70 is (70+20)/2 = 45 then we can represent D as follows

$D(x) =\left\{ \begin{array}{ll} x & \mbox{if } 0\leq x \leq 20 \\ x-20 & \mbox{if } 20\leq x < 45\\ 70-x & \mbox{if } 45 \leq x \leq 70\\ x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.$

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable $Y = D(X)$ , $Y$ is a random variable as well, remember that there is a theorem that says that

$E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx$

Where $f(x)$ is the probability mass function of X. Using the information of our problem

$E[Y] = \int\limits_{-\infty}^{\infty} D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx \bigg]\\= \frac{51}{4} = 12.75$

3 0

4 years ago

Problem 18 Last summer, Lisa and her family went on vacation. They drove from their home to Florida. They drove four days, about

Maru [420]

Answer:

2160

Step-by-step explanation:

Distance covered per day =540miles

Number of days travelled = 4 days

Therefore,the mil we s travelled altogether= 540×4= 2160

4 0

3 years ago

What is the range of y=−x^2−2x+3?<br><br> x≤−4<br><br> x≤4<br><br> x≥−4<br><br> x≥4

saveliy_v [14]

Answer:

Domain: (−∞,∞),{x|x∈R}

Range: (−∞,4],{y|y≤4

Hope this helps

4 0

4 years ago