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4 years ago

One number is 7 more than another. The difference between their squares is 161. What are the numbers?

2 answers:

3 0

X is 7 more than y
x>y then
difference betwen squares is 161 so

x=7+y
and
x²-y²=161

so
x=7+y
sub that for x in other equation

(7+y)²-y²=161
y²+14y+49-y²=161
14y+49=161
minus 49 both sides
14y=112
divide both sides by 14
y=8

sub back

x=7+y
x=7+8
x=15

the numbers are 15 and 8

liberstina [14]4 years ago

3 0

Let n be your first number and n+7 be the second. Then:
n²+161=(n+7)²
n²+161=n²+14n+49
14n=112
n=8
n+7=15
Your two numbers are 8 and 15. ☺☺☺☺

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3 years ago

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

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Given:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

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Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

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Substituting the point A(-2,3), we get;

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Thus, the coordinates of the point A' is (-2,-3)

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$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

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Substituting the point C(-1,-1), we get;

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3 years ago

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3 years ago

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Mariulka [41]

Answer:

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Step-by-step explanation:

Given that,

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The nth term of an AP is given by :

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