How do I solve 8/9x=8+4/9x

1 answer:

4 0

You subtract 4/9x frm 8/9x which is 4/9x = 8 then you multiply 9 to 8 so it is 4x = 72. After that, you divide 4 from 72 and get 18

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Write the expression using exponents.

pogonyaev

Answer:

6v^5

Step-by-step explanation:

you would leave the 6 alone. since there is 5 of the same variable, you would put 5 as your exponent

4 0

3 years ago

I drove from New York to Maryland, and then to Virginia. The total distance was 460 miles. The distance from New York to Marylan

snow_lady [41]

460 miles minus 225 miles makes
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Hope this helped.

8 0

3 years ago

Please help! Will mark the brainliest!

sesenic [268]

The domain is the set of all possible x-values which will make the function valid.
$f(x) = \frac{3}{x-2} \ \ \ \ , \ g(x) = \sqrt{x-1}$
For the given function :
The denominator of a fraction cannot be zero
The number under a square root sign must be Non negative

(a)

(1) The domain of f ⇒⇒⇒ R - {2}

Because ⇒⇒⇒ x - 2 = 0 ⇒⇒⇒ x = 2

(2) The domain of g ⇒⇒⇒ [1,∞)
Because: x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(3) $f + g = \frac{3}{x-2} + \sqrt{x-1}$
The domain of (f+g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(4) $f - g = \frac{3}{x-2} - \sqrt{x-1}$
The domain of (f-g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(5) $f * g = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}$
The domain of (f*g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(6) $f * f = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}$
The domain of ff ⇒⇒⇒ R - {2}

Because ⇒⇒⇒ x-2 = 0 ⇒⇒⇒ x = 2

(7) $\frac{f}{g} = \frac{\frac{3}{x-2} }{ \sqrt{x-1} } = \frac{3}{(x-2) \sqrt{x-1}}$
The domain of (f/g) ⇒⇒⇒ (1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2 and    x - 1 > 0 ⇒⇒⇒ x > 1

(8) $\frac{g}{f} = \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } = \frac{1}{3} (x-2) \sqrt{x-1}$
The domain of (g/f) ⇒⇒⇒ [1,∞) - {2}
Because: x - 2 = 0 ⇒⇒⇒ x = 2 and   x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1
===================================================
(b)

(9) $(f + g)(x) = \frac{3}{x-2} + \sqrt{x-1}$

(10) $(f - g)(x) = \frac{3}{x-2} - \sqrt{x-1}$

(11) $(f * g)(x) = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}$

(12) $(f * f)(x) = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}$

(13) $\frac{f}{g} = \frac{\frac{3}{x-2} }{ \sqrt{x-1} } = \frac{3}{(x-2) \sqrt{x-1}}$

(14) $(\frac{g}{f})(x) = \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } = \frac{1}{3} (x-2) \sqrt{x-1}$

7 0

3 years ago

15/7 plus 2/3plus 1/6

scoundrel [369]

Answer:

125/42

Step-by-step explanation:

15/7 + 2/3 + 1/6

90/42 + 28/42 + 7/42

125/42

2.976

4 0