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Hitman42 [59]
3 years ago
8

What does the magnitude of a vector represent?

Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

A vector's magnitude represents its length, so your answer is C, the length of a vector.

Step-by-step explanation:

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Can somebody help me? I’m already failing :(
Yuliya22 [10]

Answer:

125

Step-by-step explanation:

f(1)= the first time (32,000)

n= 9

r= .5 (each term is being mulitplied by .5 to get the next one

We have

32,000*(.5)^(9-1)

32,000*(.5)^8

=125

5 0
2 years ago
What is the distance between point A and point B?what is the ordered pair for each of the points plotted above?
Alekssandra [29.7K]

Answer:

A: (0,0), B: (3, -4), 5 units

Step-by-step explanation:

A: (0,0), B: (3, -4)

To find the distance, use the distance formula. Square-root((0-3)^2+(0-(-4))^2) ---> Square-root((-3)^2 + 4^2) ---> Square-root(9+16) ---> Square-root(25) ---> 5units.

6 0
3 years ago
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
2 years ago
A 5-lb bag of apples costs $4.50. What is the cost of apples per pound?
laiz [17]

Answer:

.9

Step-by-step explanation:

do 4.50 divided by 5 to get .9

7 0
3 years ago
Read 2 more answers
Determine the intercepts of the line. <br> -5x-4y=10
storchak [24]

Answer:

x-intercept:(-2,0)\\\\y-intercept:(0,-\frac{5}{2})

Step-by-step explanation:

The y-intercept is where x is 0 (0,y)

The x-intercept is where y is 0 (x,0)

Insert 0 as the value for x to find the corresponding y value:

-5(0)-4y=10

Simplify multiplication:

0-4y=10\\\\-4y=10

Isolate the variable. Divide both sides by 4:

\frac{-4y}{4}=\frac{10}{4}  \\\\-y=\frac{10}{4} \\\\-y=\frac{5}{2}

Make the variable positive. Multiply both sides by -1:

-1(-y)=-1(\frac{5}{2})\\\\y=-\frac{5}{2}

The y-intercept is at (0,-\frac{5}{2}).

Insert 0 as the value for y to determine the value of x:

-5x-4(0)=10

Simplify multiplication:

-5x-0=10\\\\-5x=10

Isolate x. Divide both sides by 5:

\frac{-5x}{5} =\frac{10}{5} \\\\-x=2

Multiply both sides by -1:

-1(-x)=-1(2)\\\\x=-2

The x-intercept is at (-2,0).

:Done

8 0
3 years ago
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