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masha68 [24]
3 years ago
8

2x+3y = -33 3x+6y=-57 using elimination

Mathematics
1 answer:
ella [17]3 years ago
4 0

\left\{\begin{array}{ccc}2x+3y = -33&\text{multiply both sides by 3}\\3x+6y=-57 &\text{multiply both sides by (-2)}\end{array}\right\\\\\underline{\left\{\begin{array}{ccc}6x+9y=-99\\-6x-12y=114 \end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-3y=15\qquad\text{divide both sides by (-3)}\\.\qquad y=-5\\\\\\\text{Put the value of y to the first equation}\\\\2x+3(-5)=-33\\2x-15=-33\qquad\text{add 15 to both sides}\\2x=-18\qquad\text{divide both sides by 2}\\x=-9

Answer:\ x=-9\ and\ y=-5\to(-9,\ -5)

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14.52

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<span>sin (x+pi/2)=cos x</span>
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