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3 years ago

6

100 POINTS PLEASE HELP ASAP!!! What should the following equation be multiplied by in order to eliminate the fractions? 2y/3 + 1

/3 = y/2 + 1/6
A. 6

B. 9

C. 25

D. 5

2 answers:

Dmitry_Shevchenko [17]3 years ago

8 0

I keep on getting -1 I don't know what I'm doing wrong sorry I tried

Vesnalui [34]3 years ago

3 0

The awnser for 2y+ 1/6 is 28

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Answer:

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2 years ago

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The most tickets were written on Saturday .On Saturday 325 tickets were issued

Step-by-step explanation:

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Where x represents the number of days after Sunday

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Sunday = x=0

Monday = x=1

Tuesday = x=2

Wednesday = x=3

Thursday = x =4

Friday = x=5

Saturday = x=6

Substitute x= 0

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(0)^2 + 84(0) + 37\\T(x)=37$

On Sunday 37 tickets were issued

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On Monday 115 tickets were issued

Substitute x= 2

$T(x) = -6x^2 + 84x + 37\\T(x) = -6(2)^2 + 84(2) + 37\\T(x)=181$

On Tuesday 181 tickets were issued

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On Wednesday 235 tickets were issued

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On Thursday 277 tickets were issued

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$T(x) = -6x^2 + 84x + 37\\T(x) = -6(5)^2 + 84(5) + 37\\T(x)=307$

On Friday 307 tickets were issued

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$T(x) = -6x^2 + 84x + 37\\T(x) = -6(6)^2 + 84(6) + 37\\T(x)=325$

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