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kkurt [141]
3 years ago
7

8,431.62709 which digit is in the ten-thousand place?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
6 0
6 is in the ten thousand place
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Convert 72° into grades.
kumpel [21]

Answer:

80 grades is the answer.

Step-by-step explanation:

72° into grades

1° = 10/9 grades

72° = 10/9 × 72grades

= 720/9 grades

= 80 grades

7 0
3 years ago
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Use the distributive property to simply 27-9x+15y
Solnce55 [7]

Distributive property: ⇒ a(b+c)=ab+ac

First you had to rewrite down as the nine and its should be three times three is equal to nine. Then you rewrite down as the twenty-seven and its should be nine times three is equal to twenty-seven. Next, you rewrite down as fifteen and its should be five times three is equal to fifteen.

And it gave us ⇒ =5*3y+9*3-3*3x.

Then you had to factor out by the common term of three.

And it gave us ⇒ 3(5y+9-3x)

Final answer ⇒ \boxed{=3(5y+9-3x)}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

3 0
3 years ago
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A person who weighs 60 Kg on Earth where would 54 1/2 kilograms on Venus if a child weighs 25 3/4 Kg on Earth what would this ch
Flura [38]

Answer:

Weight On Venus: 22.60 kg

Step-by-step explanation:

Being that it takes the weight of an object on earth and converts it to the weight on Venus, <em><u>the formula</u></em> is Weight on Venus= (Weight on Earth/9.81m/s2) * 8.87m/s2. To find the weight on Venus, we divide the weight on earth by the earth's force of gravity, which is 9.81m/s2. This calculates the mass of the object. Once we have the object's mass, we can find the weight by multiplying it by the gravitational force, which it is subject to. Being that Venus has a gravitational force of 8.87m/s2, we multiply the object's mass by this quanitity to calculate an object's weight on Venus.

So an object or person on Venus would weigh 90.42% its weight on earth. Therefore, a person would be lighter on Venus than on earth. Conversely, a person is 9.58% heavier on earth than on Venus.

Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds.

6 0
3 years ago
Read 2 more answers
Which equation illustrates the additive inverse property?
Minchanka [31]

Answer:

A.

Step-by-step explanation:

A negative of the same value added to positive always gives you 0

negative is inverse of positive

7 0
3 years ago
Let P(t) be a population at time t. A simple population model supposes the rate of growth of the population is proportional to t
jeka94

Answer:

(a) \dfrac{dP}{dt} =k P(t)\\(b)P(t)=Ce^{kt}

(c)P(10)\approx 272

(ii)P(1000)\approx 26.88 \times 10^{44}\\

Step-by-step explanation:

(a)The rate of growth of the population is proportional to the population, this is written as:

\dfrac{dP}{dt} \propto P(t)\\$Introducing our proportionality constant, k\\ \dfrac{dP}{dt} =k P(t)

(b)

\dfrac{dP(t)}{P(t)} =k dt\\$Take the integral of both sides\\\int \dfrac{dP(t)}{P(t)} =\int k dt\\\ln P(t)=kt+C, $C a constant of integration\\Take the exponential of both sides\\e^{\ln P(t)}=e^{kt+C}\\P(t)=e^{kt}\cdot e^C  $, (Since e^C$ is a constant, we then have:)\\P(t)=Ce^{kt}

(c)

Suppose the net birthrate of the population is .1, and the initial population is 100.

k=0.1

P(0)=100

Substitution into P(t) gives:

100=Ce^{kX0}

C=100

Therefore:

P(t)=100e^{0.1t}

(i)When t=10

P(10)=100e^{0.1 \times 10}\\=271.8\\\approx 272

(ii)When t=1000

P(1000)=100e^{0.1 \times 1000}\\=26.88 \times 10^{44}\\

8 0
4 years ago
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