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ANEK [815]
3 years ago
15

Label the number line below. Label the following fractions 1/4,1/2,3/4,2/2

Mathematics
2 answers:
dsp733 years ago
5 0
The number line should go in this order:
1/4,1/2,3/4, and 2/2
1/4=0.25
1/2=0.5
3/4=0.75
2/2=1
Georgia [21]3 years ago
5 0
If we are making a number line then it should go in order like this:
 1/4,1/2,3/4, and 2/2
1/4=0.25
1/2=0.5
3/4=0.75
2/2=1 (whole)
 you  just make then a decimal and put them in order:-) 
hope this helps!! 
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lana66690 [7]

Answer: - 32

Step-by-step explanation:

-8 + (-24)

Infront of the Positive is a one.

-8 +1 (-24)

If we follow order of operations which is parentheses, exponents, multiply divide, add, and subtract, we can see we need to multiply/ distribute first. And a positive times a negative is a negative.

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Now we put the two numbers together.

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This is the answer

6 0
3 years ago
An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 340 feet of antique
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Answer:

The dimensions of the garden is 102 feet by 68 feet

Step-by-step explanation:

Here, we want to get the width and length of the garden

The perimeter is represented by the length of the fencing

From the question;

w = 2l/3

The formula for the perimeter is;

P = 2(l + w)

Thus;

340 = 2(l + 2l/3)

170 = (l + 2l/3)

Multiply through by 3

510 = 3l + 2l

5l = 510

l = 102 feet

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w = 2/3 * 102

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3 years ago
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patriot [66]

1457.50 dollars or 1458 dollars rounded


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3 years ago
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
Please help!<br><br>In circle Y, what is m?<br><br><br>82°<br><br>100°<br><br>106°<br><br>118°
ss7ja [257]

Answer:

<em>The correct option is:  82°</em>

Step-by-step explanation:

In the given diagram, two chords RT and SU are intersecting.

According to the <u>Angle of intersecting chord theorem</u>, "<em>If two chords intersect inside a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle</em>."

That means here......

94\°=\frac{1}{2}(m\widehat{RS}+m\widehat{TU})\\ \\ 94\°=\frac{1}{2}(106\°+m\widehat{TU})\\ \\ 2(94\°)=106\°+m\widehat{TU}\\ \\ 188\°=106\°+m\widehat{TU}\\ \\ m\widehat{TU}=188\°-106\°=82\°

So, the measure of arc TU is 82°

5 0
3 years ago
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