As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Answer: Provide an image please?
Step-by-step explanation:
Answer: (b+5)(b-5)
Step-by-step explanation:
both b^2 and 25 are square numbers, so square root both of them to give b and 5, then put into brackets with a + and -
Answer:
{xlx > 10}
Step-by-step explanation:
The lowest value of x is about -8, which is greater than negative 10
y = mx + b, where b is the y intercept.
D, or "12" is the answer.
Best of luck.
