Answer:
3+(6-2)*4=19
Step-by-step explanation:
Due to PEMDAS, it would first be required to do "6-2", which is 4.
Then, the 4 in the parenthesis is multiplied by the 4 on the outside, making 16.
Finally, 3 would be added to 16, making 19.
The answer is D) because C) and B) are biased and would not be reasonable and A) has no guarantee of every third child being 12.
Find real values of the number a for which a.i is a solution of the polynomial equation. ...
u,v and w are the three roots of the equation z3 - 1 = 0 . ...
Calculate all solutions of |z-1|.|z-1|=1. ...
The equation z3 - (n + i) z + m + 2 i = 0. ...
Let z' the conjugate complex number of z.
There ya go! The answer is 8 rows. Added a picture to show you my work :)
