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Iteru [2.4K]
3 years ago
6

A baseball team won 40% of its first 30 games. The team then won 65% of its next 60 games. Approximately what percent of the gam

es did the team win?
A. 47
B. 51
c. 53
D. 57
Mathematics
1 answer:
ozzi3 years ago
3 0

Answer:

B. 51

Step-by-step explanation:

To find the answer, you need to multiply the percentage by the number of total games. To multiply the percentage, you need to transform it into a decimal. To do that, simply move the decimal in 40 two spaces to the left. Now you have 0.4. multiply 0.4*30=12. So out of 30, the team won 12 games. Do the same thing with 65% of 60 games. 0.65*60=39. So out of 60, the team won 39. Add the amount of games won total to get 51. Remember the technique in bold! Hope this Helps!

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Nimfa-mama [501]

I think the answer is 3

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2 years ago
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At the beginning of the week, a puppy weighed 5/14 pounds. During the week, the puppy gains 8 ounces.
Mekhanik [1.2K]

Answer:

51/12

as a mixed number

4 1/4

Step-by-step explanation:

first you add 8 to 4 which is 12

so the improper fraction would be 51/12

how to turn it in to a mixed number in simplest form

step 1 - Find Whole Number

Calculate out how many times the denominator goes into the numerator. To do that, divide 51 by 12 and keep only what is to the left of the decimal point:

51 / 12 = 4.2500 = 4

Step 2 - Find New Numerator

Multiply the answer from Step 1 by the denominator and deduct that from the original numerator.

51 - (12 x 4) = 3

Step 3 - Put Together

Keep the original denominator and use the answers from Step 1 and Step 2 to get this:

4  

   3  

   12  

Step 4 - Minimize

Minimize the fraction part from Step 3 by dividing the numerator and denominator by 3, which is the greatest common factor, to get the final answer. 51/12 as a Mixed Number is:

4  

   1  

   4  

5 0
2 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
Homework, pls help ( 10 points )
NeTakaya
4(8x + 3y)

= 32x + 12y
4 0
3 years ago
Help please!!.Use estimation to check the answer to this story problem.
romanna [79]

Answer:

C. 70+20

Step-by-step explanation:

6 0
3 years ago
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