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The answer to your question would be as followed:
The most precise measurement for the cylinder you are mentioning is <em><u>B. 43.0mL</u></em>
Answer:
the molecular formula of the compound is N2O4
Explanation:
- Find the empirical formula
mole of N present = mass of N divided by molar mass of N = 0.140/14 = 0.01 mole
mole of O present = mass of O divided by molar mass of O = 0.320/16 = 0.02 mole
Divide both by the smallest number of mole to determine the coefficient of each, the smallest number of mole is 0.01 thus:
quantity of N = 0.01/0.01 = 1
quantity of O = 0.02/0.01= 2
thus the empirical formula = NO2
- Now determine the molecular formula by finding the ratio of molecular formula and empirical formula
Molar mass of molecular formula = 92.02 amu = 92.02 g/mole
Molar mass of empirical formula NO2 = (14 + (16 x 2)) = 46 g/mole
the x factor = 92.02/46 = 2
Molecular formula = 2 x NO2 = N2O4
Answer:
POLAR COVALENT
Explanation: A polar covalent bond is a covalent bond in which the atoms have an unequal attraction for electrons and so the sharing is unequal. In a polar covalent bond, sometimes simply called a polar bond, the distribution of electrons around the molecule is no longer symmetrical.
From the calcuation, the percent ionic character of the bond is 70%
<h3>What is percent ionic character?</h3>
The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.
We can use the formula; 100(1 - e^(-ΔEN² / 4))
EN = χB − χA * 100/1
EN = 3.5 - 1.5 = 1
100(1 - e^(-1)^2/4)
= 70%
Learn more about percent ionic character:brainly.com/question/7034446
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