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den301095 [7]
3 years ago
12

Calcium, carbon dioxide, and water combine to form calcite. True or False?

Chemistry
2 answers:
Alex3 years ago
6 0

Answer:FALSE

Explanation:I HOPE THIS HELPS YOU ALOT

tensa zangetsu [6.8K]3 years ago
5 0

Hi!

Answer - False

"Calcite is the transformation of shell, coral, fecal and algal debris into calcite during diagenesis."

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Octasulfur reacts with pure oxygen to produce sulfur dioxide. Determine the percent
Margaret [11]

Answer:

Octasulfur is just S8. Eight S atoms in

a sort of crown shape. Sulfur Dioxide is a gas, SO2. Does that help?

Explanation:

5 0
4 years ago
Which of the following statements are correct? Rewrite the incorrect statements to correct them.
Mariana [72]
A) true
b) false  The atomic mass is never less than the atomic number.
c) this one is a bit tricky.  For hydrogen, the atomic mass can equal the atomic number IF you are rounding the mass to the nearest whole number. That only works for hydrogen, though
d) false  The larger the element, the more neutrons that are needed to keep the nucleus stable.
e) true
f) true
7 0
3 years ago
For the reaction, A(g) + B(g) => AB(g), the rate is 0.385 mol/L.s when the initial concentrations of both A and B are 2.00 mo
Tanya [424]

Answer : The rate for a reaction will be 0.14Ms^{-1}

Explanation :

The balanced equations will be:

A(g)+B(g)\rightarrow AB(g)

In this reaction, A and B are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[A]^2[B]^1

or,

\text{Rate}=k[A]^2[B]

Now, calculating the value of 'k' by using any expression.

\text{Rate}=k[A]^2[B]

0.385=k(2.00)^2(2.00)

k=0.0481M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(0.0481)\times (1.48)^2(1.32)^1

\text{Rate}=0.14Ms^{-1}

Therefore, the rate for a reaction will be 0.14Ms^{-1}

7 0
4 years ago
PLZ HELP
riadik2000 [5.3K]
Too many to know in the world.
8 0
4 years ago
Which property to put in which
NeTakaya
In the Proton category: symbol p, and +1 charge
In the Neutron category: symbol n, 0 charge
In the Electron category: symbol e, -1 charge
6 0
3 years ago
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