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xxMikexx [17]
3 years ago
12

How is the distributive property different from properties of equality?

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
Distributive property distributes numbers in any way and the answer will be the same. Btw, this isn't chemistry.
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Which element is a liquid at STP? 1.bromine 2.cesium 3.francium 4.iodine
nexus9112 [7]
Bromine. both Bromine and Mercury are both a liquid at STP. :)
4 0
3 years ago
a sample of sucrose was burned in a calorimeter, and 41,600 joules oh heat energy were released. which statement is true about t
Gala2k [10]

It absorbed 41,600 joules.

Explanation:

If the sample of sucrose burnt in the calorimeter releases 41600Joules of heat, then the water in the calorimeter will absorb 41600J.

 The heat lost by burning the sucrose in the calorimeter is also the heat gained by the water therein.

A calorimeter is a device by prevents heat loss to the environment in any form.

It is specially designed to minimize heat loss by conduction, convection radiation.

Therefore, since no heat is lost, the heat released by burning the sucrose is used in heating the water there.

learn more:

Specific heat brainly.com/question/7210400

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5 0
3 years ago
Tuliskan persamaan tetapan kesetimbangan untuk reaksi-reaksi berikut a. Fe3+(aq) + SCN– (aq) ↔ FeSCN3+(aq) b. 3Fe(s) + 4H2O(g) ↔
nevsk [136]

Answer:

a. K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}

b. K_p = \dfrac{[H_2]^4}{[H_2O]^4}

Explanation:

Untuk semua jenis reaksi umum:

aA + bB\iff cC + dD

Konstanta kesetimbangan K_c = \dfrac{[C]^c [D]^d}{[A]^a[B]^b}

Dari pertanyaan yang diberikan:

a. Fe3^+_{(aq)} + SCN^-_{ (aq)} \iff FeSCN^{3+}_{(aq) }

Konstanta kesetimbangan:

K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}

b. 3Fe_{(s)} + 4H_2O_{(g)} \iff Fe_3O_4_{(s)} + 4H_{2(g)}

Konstanta kesetimbangan untuk tekanan parsial K_p

K_p = \dfrac{[H_2]^4}{[H_2O]^4}

Karena Fe3O4 (s) hadir sebagai padatan.

8 0
3 years ago
Which arrow represents the activation energy for the forward reaction
ValentinkaMS [17]

Answer:

B

Explanation:

found it from a person wjwjdjjanqnqq

4 0
2 years ago
Read 2 more answers
Calculate the volume of a 0.5M solution containing 20g of NaOH
Tju [1.3M]

Answer:

1L

Explanation:

First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:

Mass = 20g

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Number of mole =?

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 20/40 = 0.5mol

From the question given, we obtained the following data:

Molarity = 0.5M

Mole = 0.5mole

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.5/0.5

Volume = 1L

6 0
3 years ago
Read 2 more answers
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