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3 years ago

Find the area of the figure. (Sides meet at right angles.)

Mathematics

1 answer:

kvasek [131]3 years ago

8 0

Answer:

The area of the figure is 48 cm^2

Step-by-step explanation:

Break it into 3 different quadrilaterals and find the area of each one.

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Which of the following shows the correct solution steps and solution to 7x- 4 = -182 7x - 4 = -18 71 - 4+4= -18 + 4 72 = -14 A.

erica [24]

Answer/Step-by-step explanation:

7x- 4 = -182

Step:

Add 4 to both sides

7x - 4 + 4 = -182 + 4

Simplify

7x = -178

Divide both sides by 7

7x/7 = -178/7

Simplify

x = -178/7

Decimal form = -25.4285714286

~lenvy~

3 0

2 years ago

Read 2 more answers

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

Please help with A, B, and C

makkiz [27]

A. 75 degrees because the angle creates by the car and the opposite 75 degree are vertical angles meaning that their congruent
B. 75 degrees because the 4the street and the 3rd streets are both Patel meaning that the angle of the car and the 75 degree angle on northeast angle of the fourth street are corresponding angels
C. 105 degrees because the 180 degrees which is the angle of a straight line subtracted from the 75 degree gives the answer of 105 degrees

4 0

3 years ago

(3×+5)(2×+10)= then x=

katen-ka-za [31]

X= -5/3 & x=5
I got this by using the quadratic formula.

8 0

3 years ago

The average capacity of five containers is 13 liters. A container with a capacity of 7 liters is added to the set of 5. What is

Zepler [3.9K]

Answer:

12 liters

Step-by-step explanation:

Let the capacity sum of the 5 containers be X

13 = X / 5

X = 65 liters

Average capacity of the six = ( 65 + 7 )/ 6 liters

= 72/6 liters

= 12 liters

4 0

2 years ago