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marin [14]
4 years ago
14

True or false? atomic bombd work by atomic fission​

Chemistry
1 answer:
Law Incorporation [45]4 years ago
5 0
I’d go with true. Most nuclear bombs use both fission and fusion but now all of them. And all bombs need fission to work.
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Marcy uses pH strips to measure the pH of water samples from several ponds in the city park. Which reason explains why using a p
Goryan [66]
First question:

As the pH meter gives a specific level of acidity instead of a physical change, it is more accurate in numbers making it easier to distinguish smaller differences in pH.

2nd question:

The pH meter gives a digital readout.

The pH meter uses numbers instead of colors.

<span>The pH meter can distinguish between smaller differences in pH than pH strips can.
</span>
The one not mentioned above isn't true ^
6 0
4 years ago
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The activation energy (E*) for 2N2O ---&gt; 2N2 + O2 is 250 KJ. If the k for this reaction is 0.380/M at 1001oK, what will k be
Sedbober [7]

Answer:

Explanation:

GIven that:

The activation energy = 250 kJ

k₁ = 0.380 /M

k₂ = ???

Initial temperature T_1 = 1001 K

Final temperature T_2 = 298 K

Applying the equation of Arrhenius theory.

In \dfrac{k_2}{k_1 }= \dfrac{Ea}{R}( \dfrac{1}{T_1 }- \dfrac{1}{T_2})

where ;

R gas constant = 8.314  J/K/mol

In \dfrac{k_2}{0.380 }= \dfrac{250 * 10^3}{8,314}( \dfrac{1}{1001 }- \dfrac{1}{298})

In \dfrac{k_2}{0.380 }= -70.8655

\dfrac{k_2}{0.380 }= e^{-70.8655}

\dfrac{k_2}{0.380 }= 1.67303256 \times 10^{-31}

{k_2}= 1.67303256 \times 10^{-31} \times {0.380 }

{k_2}= 6.3575 \times 10^{-32}  /M .sec

Half life:

At 1001 K.

t_{1/2} = \dfrac{In_2}{k_1}

t_{1/2} = \dfrac{0.693}{0.38}

t_{1/2} = 1.82368 secc

At 298 K:

t_{1/2} = \dfrac{0.693}{6.3575 \times 10^{-32}}

t_{1/2} =1.09 \times 10^{31} \ sec

3 0
3 years ago
Classifying Animals
MrMuchimi

Answer:

I believe:

vertebrate: hummingbird, tiger, lobster

invertabrate: lizard, octopus, mosquito

4 0
3 years ago
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A reaction is in equilibrium as shown: A + B C + D. Calculate the equilibrium constant in the final concentrations stabilized at
Butoxors [25]

Answer:

K = 0.167

Explanation:

The equilibrium constant, K of a reaction, is defined as the ratio of the concentrations of products and concentrations of reactants.

For the reactions:

A + B ⇄ C + D

For the definition, K is:

K = [C] [D] / [A] [B]

K = [4.0M] [4.0M] / [9.6M] [10.0M]

<h3>K = 0.167</h3>

8 0
3 years ago
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slava [35]

Answer:

I think is b

Explanation:

if im wrong, heres some information:

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3 0
3 years ago
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