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mash [69]
3 years ago
10

Consider the following reaction:

Chemistry
2 answers:
mestny [16]3 years ago
7 0
Equation: NH4HS(s) <=> NH3 (g) + H2S(g)

Kc = [NH3]eq[H2S]eq; where eq subscripts are used to indicate that those are the concentrations at equilibrium

 Kc= 0.272 * 0.365 =0.09928

posledela3 years ago
4 0

Answer : The equilibrium constant is, 9.928\times 10^{-2}

Solution : Given,

Equilibrium concentration of NH_3 = 0.272 M

Equilibrium concentration of H_2S = 0.365 M

The given balanced equilibrium reaction is,

NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)

The expression for equilibrium constant will be,

K_c=\frac{[NH_3][H_2S]}{[NH_4HS]}

Now put all the given values in this formula, we get  value of equilibrium constant.

K_c=\frac{(0.272)\times (0.365)}{1}

K_c=0.09928=9.928\times 10^{-2}

Therefore, the equilibrium constant is, 9.928\times 10^{-2}

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