The sum of two numbers is 21. The larger number is 6 less than twice the smaller number. Find the two numbers.
1 answer:
The sum of two numbers x + y = 21 x = smaller number y = larger number Larger Number = y = (2x -6) Substitute (2x - 6) for y x + y = 21 x + (2x - 6) = 21 3x - 6 = 21 3x = 21 + 6 3x = 27 3x / 3 = 27 / 3 x = 9 Smaller number = x = 9 Find the larger number by inserting 9 into (2x - 6) (2x - 6) (2(9) - 6) 18 - 6 12 So x = 9 y =12 Check our answer by inserting x = 9 and y = 12 into x + y = 21 x + y =21 9 + 12 = 21 21 = 21 So since we have 21 = 21 we know our answer is correct.
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