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abruzzese [7]
3 years ago
9

Hellppp plz will mark brainliestttt

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

not a function i think

Step-by-step explanation:

have a nice day hope this helps

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20, 10, 40, 10, 60, 20, 80, 60,<br> 100, 240, 120, ______,_____
Firlakuza [10]

Answer:

1200, 140

Step-by-step explanation:

for easier: (20), 10, (40), 10, (60), 20, (80), 60, (100), 240, (120), 1200, (140)

numbers already (), add 20 per number

=== so (20, 40, 60, 80, 100, 120, answer 140)

numbers that are not turned () are 10x1x2x3x4x5

=== so 10, 10, 20, 60, 240, 1200

5 0
3 years ago
Read 2 more answers
a store has 18 red beach balls and 17 green beach balls in boxes of 5 beach balls each how many boxes of beach Balls are in stor
Stells [14]
10 beach balls are needed
4 0
3 years ago
Read 2 more answers
I NEED HELP FAST ON #6 PLEASE HELP!
Advocard [28]

Answer:

money owed (in order): $850, $870.40, $891.29, $912.68

Step-by-step explanation:

The formula is

money owed = amount owed the previous week + amount owed previous week × interest rate (in decimal form)

so thats:

money owed = amount owed the previous week + amount owed previous week × 0.024

we can simplify that to:

money owed = amount owed the previous week x (1.024)

after 0 weeks:

$850 (just started, no interest added)

after 1 week:

$870.40

after 2 weeks:

$891.29

after 3 weeks:

$912.68

4 0
4 years ago
The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches.
nalin [4]

Answer:

option C 13.5%

Step-by-step explanation:

As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as

P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]

P(64<X<66.5)=P(-2<Z<-1)

P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)

P(64<X<66.5)=0.4772-0.3413=0.1359

Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.

If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.

5 0
4 years ago
In the jone school library,10/20 of the computers have scanners.in simplest form, which fraction of the computers have scanners?
n200080 [17]

Answer:

1/2

Step-by-step explanation:

5 0
3 years ago
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