-5x - 4y = 10 what are the intercepts

Mathematics

2 answers:

dybincka [34]3 years ago

4 0

Ummmmmm idk x intercepts-2,0 I guess

topjm [15]3 years ago

3 0

X intercept (-2,0)
Y intercept (0,-5/2)

You might be interested in

Help please with some 7th grade math

ivolga24 [154]

ANSWER: 3 walls

EXPLANATION: Since we know that with 1/4 can he can paint 3/4 of a wall, and 4/4 is equal to one can of paint, all you would have to do is multiply 3/4 by 4 since 1/4 + 1/4 + 1/4 + 1/4 = 4/4 (Also can be written 4(1/4)=4/4)

6 0

2 years ago

The height of a trapezoid is 8 in. And it's area is 96 squared inch. One base of the trapezoid is 6 inches longer than the other

MaRussiya [10]

we name bases k , k+6. so

area: 96= (k + k+6).8/2

=> 2k+6= 24 => k=9

7 0

3 years ago

What is log15 2^3 rewritten using the power property?

OlgaM077 [116]

ANSWER

$log_{15}( {2}^{3} ) = 3 \: log_{15}( {2} )$

EXPLANATION

According to the power property of logarithms:

$log_{x}( {y}^{n} ) = n \: log_{x}( {y} )$

The given logarithm is

$log_{15}( {2}^{3} )$

When we apply the power property to this logarithm, we get,

$log_{15}( {2}^{3} ) = 3 \: log_{15}( {2} )$

8 0

3 years ago

Read 2 more answers

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$