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wolverine [178]
3 years ago
13

How do you?...Multiply out and simplify 10(2x-1)-20x?

Mathematics
2 answers:
Xelga [282]3 years ago
7 0
10(2x-1)-20x=(omitting\ the bracket)= 20x-10-20x=-10\\\
Result: -10
svp [43]3 years ago
5 0
10(2x-1)-20x\\\\=10\times2x-10\times1-20x\\\\=20x-10-20x\\\\=-10
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How many solution does -3 (4 - 3x) = 9x - 12
daser333 [38]

Answer: infinite solutions

Step-by-step explanation:

(−3) (4) + (−3) (−3x) = 9x + −12

−12 + 9x = 9x + −12

9x − 12 = 9x − 12

9x − 12 − 9x = 9x − 12 − 9x

−12 = −12

−12 + 12 = −12 + 12

0 = 0

3 0
3 years ago
Find the value of x and HI. H and J are the endpoints​
a_sh-v [17]

Answer:

x = 6

HI = 29

Step-by-step explanation:

✔️HI = ½(AB) => Triangle Mid-segment Theorem

HI = 5x - 1

AB = 58

Plug in the values and solve for x

5x - 1 = ½(58)

5x - 1 = 29

Add 1 to both sides

5x - 1 + 1 = 29 + 1

5x = 30

Divide both sides by 5

5x/5 = 30/5

x = 6

✔️HI = 5x - 1

Plug in the value of x

HI = 5(6) - 1

HI = 30 - 1

HI = 29

5 0
2 years ago
Please please helppppppppppppp
Leya [2.2K]

Answer:

C

Step-by-step explanation:

Both lines start and end on x = 3

The lower line has a positive slope and a y- intercept of - 2

The lower line has an open circle at it's endpoint indicating it cannot equal 3

x - 2 for x < 3

The upper line has a positive slope and a y- intercept of - 1, if we project the line. The line has a closed circle at it's start indicating it can equal 3, thus

x - 1 for x ≥ 3

Hence

x - 1 if x ≥ 3

x - 2 if x < 3 → C

3 0
3 years ago
How to solve this problem that don't nor know
Paraphin [41]
Well, for number 23 you have to figure out what n is. In order to do that you have to multiply different numbers to figure out the number for n. I hope this helps and have a wonderful day.
6 0
3 years ago
Read 2 more answers
Find the center and radius of the circle whose equation is x2 + y2 - 6x-2y+4= 0
marin [14]

Answer:

The center of the circle = (3, 1)

The radius of a circle is given as r = √6

Step-by-step explanation:

The equation of a circle is given as:

( x - a)² + (y - b)² = r²

where ( a , b) = center of the circle

r = radius of the the circle

In the question above, we are given the equation of a circle as

x² + y² - 6x - 2y + 4= 0

In order to find the center and radius of this circle we would use completing the square method to solve it

Step 1

Collect the like terms

x² - 6x + y² - 2y + 4= 0

Step 2

Complete the square for both x and y

x² - 6x + (-6/2)² + y² - 2y + (-2/2)² = - 4 +(- 6/2)² + (-2/2)²

x² - 6x + (-3)² + y² - 2y + (-1)² = -4 + (3)² + (1)²

x² - 6x + 9 + y² - 2y + 1 = -4 + 9 + 1

(x² - 6x + 9) + (y² - 2y + 1 )= -4 + 9 + 1

(x² - 3x - 3x +9) + ( y² - y - y +1) = 6

x(x - 3) -3( x - 3) + y( y - 1) - 1( y - 1) = 6

(x - 3) (x -3) +(y - 1) ( y - 1) = 6

(x - 3)²(y - 1)² = 6

Since,

The equation of a circle is given as:

( x - a)² + (y - b)² = r²

where ( a , b) = center of the circle

r = radius of the the circle

The equation of the the circle for the above question is calculated as:

(x - 3)²(y - 1)² = 6

where ( a , b) = center of the circle = (3, 1)

r = radius of the the circle

r² = 6

r = √6

8 0
2 years ago
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