Help Please!!!!. I need help with this assignment.

Mathematics

1 answer:

Akimi4 [234]3 years ago

5 0

Find the slopes of each line.

We can use rise/run or m= (x2-x1)/(y2-y1)

But, before going on, the green line is completely straight. A slope is a level of decreasing or increasing value. It is constant, it is the same.

The slope of L3 (green) = 0. (B. m=0)

Let's find the slopes of the other two.

First, blue. Find two points. (3,-2) (5,-1)

m= (-1-(-2))/ (5-3)

m= (-1+2)/(5-3)

m= (1/2) or 0.5

L1= 0.5 (A. m=0.5)

So, It takes a while to find slope- so I won't solve the last one. But, we know that...

L2= C. m= -1.6

I hope this helps!
~kaiker

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Evaluate the expression<br><br> x^2 (y - 2)<br> —————, if x=3, and y= -1<br> 3y

vitfil [10]

Answer:

$\huge\boxed{\sf 9}$

Step-by-step explanation:

$\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

4 0

3 years ago

Read 2 more answers

Lesson 16

Goshia [24]

Answer:

546 ft³

Step-by-step explanation:

In the figure attached, the top view of the pool is shown. It can be decomposed into a trapezoid which height is 12 ft and which bases are 9 ft and 11 ft; and a rectangle which height is 1.5 ft and and it base is 11 ft.

Area of the trapezoid: (9 + 11)/2 * 12 = 120 ft²

Area of the rectangle: 1.5*11 = 16.5 ft²

Total area: 120 + 16.5 = 136.5 ft²

Volume of the pool: Total area * deep = 136.5 * 4 = 546 ft³