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stellarik [79]
3 years ago
11

Please answer it correctly and please show work please help me if it’s correct I will mark you brainliest

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

210 hours

Step-by-step explanation:

<u>Step 1:  Make an expression</u>

(2/3 * 1575) / 5

<u>Step 2:  Multiply</u>

(2/3 * 1575)/5

(1050) / 5

<u>Step 3:  Divide</u>

(1050) / 5

210 hours

Answer:  210 hours

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Vlad [161]
2 * x/100 = 8

x/100 = 4

x = 400

400%
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2abc - 3ab if a=2 b=-3 and c=4
Margarita [4]
2abc - 3ab ║ 2 (2) (3) (4) - 3 (2) (3)

You would multiply and the products - you are going to subtract
2 × 2 × 3 × 4 = 48
3 × 2 × 3 =     - 18
                    -------
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7 0
3 years ago
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Please I need ASAP. First one to answer will get Brainyist.
Rzqust [24]

Answer:

I'm just here for my points sorry bro

4 0
3 years ago
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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
My sister went QUaCk and my heart QuaKeD
labwork [276]

Answer:

That's nice

But it should've YEETED

Step-by-step explanation:

4 0
3 years ago
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