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fenix001 [56]
2 years ago
10

Find the first 3 interations here: g(x)=-1|x-2|+3 if you have an initial value of 0.5

Mathematics
1 answer:
makvit [3.9K]2 years ago
6 0

Answer:

  • The first iteration = 1.5
  • The 2nd iteration = 2.5
  • The third iteration = 2.5

Step-by-step explanation:

Considering the function

  • g\left(x\right)=-1\:|\:x\:-\:2\:|\:+\:3
  • As the initial value = 0.5
  • In order to determine the next iterate, apply the function g(x) to the previous one.

DETERMINING FIRST ITERATION:

g\left(0.5\right)=-1\:|\:0.5\:-\:2\:|\:+\:3

          = -1 | 0.5 - 2 | + 3

          = -1 | -1.5 | + 3

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a ; | -1.5 | =  1.5

          =-1.5+3  

          = 1.5

Thus, the first iteration = 1.5

DETERMINING SECOND ITERATION:

Putting the value of first iteration i.e. 1.5 into the original function to determine the 2nd iteration.

g\left(1.5\right)=-1\:|\:1.5\:-\:2\:|\:+\:3

as    1.5 - 2 = -0.5

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a ;  | -0.5 | =  0.5

        =-0.5+3

        = 2.5

Thus, the 2nd iteration = 2.5

DETERMINING THIRD ITERATION:

Putting the value of second iteration i.e. 2.5 into the original function to determine the 2nd iteration.

g\left(2.5\right)=-1\:|\:2.5\:-\:2\:|\:+\:3

\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0

         =-0.5+3        as  2.5-2=0.5

         = 2.5

Thus, the third iteration = 2.5

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Step-by-step explanation:

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Multiply the second equation by -2 to use elimination

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Add this to the first equation

10x+2y=42

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Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

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