Answer:
The length of AB = 97/3 units
Step-by-step explanation:
We know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the equation becomes
7x+2 = 4x+15
7x-4x = 15-2
3x = 13
x = 13/3
So, the length of CD = 7x+2 = 7(13/3)+2
= 91/3 + 2
= 97/3
And, the length of BC = 4x+15 = 4(13/3) + 15
= 97/3
- We already know that a rhombus is a quadrilateral whose four sides all have the same length.
Thus, the length of AB = 97/3 units
Answer: GO TO MY ACCOUNT AND AWNSER MY QUESTION TEN I'LL AWNSER YOURS
Step-by-step explanation:
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Vertex is (-3 , 21 ) you can put <span>y=-2x^2-12x+3 in google and you will see the function</span>
A number squared would be x squared (x^2)
The product of x squared and ten is 10x^2
Then subtract nine
10x^2 - 9
