<span>f(x<0)=-f(x>0)=-x^2+5x+12
When x>0, x^2-5x-12=12, x=8, y=12
Therefore, f(x)=12 goes through point (8,12).</span>
Answer:
1600 integers
Step-by-step explanation:
Since we have a four digit number, there are four digit placements.
For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.
For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.
For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers
Answer:
The answer is -23
Step-by-step explanation:
The least common multiple of 24, 27, and 108 is 3
