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3 years ago

PLEEEEEAAAASSSSEEEEE HELP

Mathematics

1 answer:

Goryan [66]3 years ago

4 0

A tangent line is located outside the circle and only touches the circle at one point.
The tangent line in this picture would be line BC.

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A book that cost $58 is now increased by 25 what is the new cost

Dennis_Churaev [7]

Answer:

the new cost is 83

Step-by-step explanation:

58 plus 25 is 83

3 0

3 years ago

Solve for a and x in ax^2=48

Gelneren [198K]

Answer:

$ax^2 = 48\\a = \frac{48}{x^2}$

$ax^2 = 48\\x^2 = \frac{48}{a} \\x = \frac{\sqrt{48} }{\sqrt{a} } \\x = \frac{4\sqrt{3} }{\sqrt{a}} \\x = \frac{4\sqrt{3a} }{a}$

6 0

3 years ago

Which is the simplest form of this algebraic expression? -(6x + 2y) + 4(2x - y)

Marrrta [24]

The simplest form of -(6x+2y)+4(2x-y) = -2(-x+3y).

3 0

4 years ago

Read 2 more answers

To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?

eimsori [14]

Answer:

You should multiply the expression by $\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$

Explanation:

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

This means that:

The conjugate of a + b would be a - b

Now, the given expression is $\frac{2}{\sqrt{13}+\sqrt{11}}$

Consider the denominator:

From the above, we can conclude that the conjugate of $\sqrt{13}+\sqrt{11}$ is $\sqrt{13}-\sqrt{11}$

And, remember that we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

Therefore:

You should multiply the expression by $\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$ in order to rationalize the denominator

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Which statement describes the behavior of the function f(x)=3x/4-x?

Oksana_A [137]

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is