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finlep [7]
3 years ago
13

Please help

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
Part 1
1) The positive integers          ----------->  <span>D.) The natural numbers
</span>2.) An ordering of quantities  -----------> <span>B.) A sequence
</span>3.) 2, 4, 8, 16, . . ., 256            ----------->  <span>A.) An example of a finite sequence
</span>4.) 1, 3, 5, 7, . . .                        ----------->  <span>E.) An example of an infinite sequence
</span>5.) No first term is available   ----------->  C.) The reason the numbers . . . -4, -2, 0, 2, 4, . . . are not a sequence
Part 2
a_n=n^2+2\\ a_1=1+2=3\\ a_2=4+2=6\\ a_3=9+2=11\\ a_4=16+2=18\\ a_5=25+2=27
The answers is A.
Part 3
a_n=-1(\frac{1}{3})^{n-1} \\ a_1=-1(\frac{1}{3})^{1-1}=-1\\ a_2=-1(\frac{1}{3})^{2-1}=-\frac{1}{3}\\ a_3=-1(\frac{1}{3})^{3-1}=--\frac{1}{9}\\ a_4=-1(\frac{1}{3})^{4-1}=--\frac{1}{27}\\ a_5=-1(\frac{1}{3})^{5-1}=--\frac{1}{81}\\
The answers is B.
Part 4
The pattern in this sequence is:
a_n=2a^nb^{n-1}
Let's list first six terms:
a_n=2a^nb^{n-1}\\&#10;a_1=2a^1b^0=2a\\&#10;a_2=2a^2b^1=2a^2b\\&#10;a_3=2a^3b^2\\&#10;a_4=2a^4b^3\\&#10;a_5=2a^5b^4\\&#10;a_6=2a^6b^5\\
This is a infinite sequence. The patern is obvious and we could find any term within the sequence.


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