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3 years ago

30 PTS, Need assistance!

2 answers:

10 0

The types of problems found on ancient papyri, books, and tablets focuses primarily on problems that relate to daily life. The solution methods for many ancient cultures are generally verbal, with mathematical statements written out in words. Why did most ancient cultures primarily write out their mathematical texts in words?

Answer:

Most ancient societies had symbols to represent numbers, but they did not have symbols to represent operations or unknown quantities. Thus, the problems and solutions to the problems had to be written in word form.

Alja [10]3 years ago

8 0

Answer:

The following are the correct statements regarding mathematics in the Egyptian, Chinese, and Babylonian cultures:

Both Egyptian and Chinese number systems use base 10.

All three cultures had unique symbolism to represent their numbers . (Earlier symbols were used to depict things)

There are two primary sources for ancient Egyptian mathematics

(The primary sources are the Rhind Papyrus and the Moscow Papyrus)

Step-by-step explanation:

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3 years ago

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3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

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8 0

3 years ago

Samuel ran 8 miles on Monday, 4.25 miles on Tuesday, and 3.3 miles on

Vaselesa [24]

Answer: 15.55 miles

Step-by-step explanation:

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3 years ago

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Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t

Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0

3 years ago