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Kitty [74]
3 years ago
5

30 PTS, Need assistance!

Mathematics
2 answers:
Oksana_A [137]3 years ago
10 0

The types of problems found on ancient papyri, books, and tablets focuses primarily on problems that relate to daily life. The solution methods for many ancient cultures are generally verbal, with mathematical statements written out in words. Why did most ancient cultures primarily write out their mathematical texts in words?

Answer:

Most ancient societies had symbols to represent numbers, but they did not have symbols to represent operations or unknown quantities. Thus, the problems and solutions to the problems had to be written in word form.

Alja [10]3 years ago
8 0

Answer:

The following are the correct statements regarding mathematics in the Egyptian, Chinese, and Babylonian cultures:

Both Egyptian and Chinese number systems use base 10.

All three cultures had unique symbolism to represent their numbers . (Earlier symbols were used to depict things)

There are two primary sources for ancient Egyptian mathematics  

(The primary sources are the Rhind Papyrus and the Moscow Papyrus)

Step-by-step explanation:

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fgiga [73]

For this case we have the following function:

y=\frac{3}{4}x^2

When evaluating x = 2 in the given function we have:

y=\frac{3}{4}(2)^2

Rewriting we have:

y=\frac{3}{4}(4)

y=3

Therefore, the pair ordered for this point is given by:

(x, y) = (2,3)

The ordered pair of the table for x = 2 is:

(x, y) = (2,4)

Therefore, the table is incorrect for x = 2

Answer:

The row in the table is incorrect for:

x=2

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3 years ago
What is the sum when two opposites are combined?
Dafna11 [192]
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3 0
3 years ago
Read 2 more answers
The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

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