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3 years ago

HEY YA'LL 30 PTS FOR 1 PROBLEM! Given: m∠EYL=1/3 the measure of arc EHL Find: m∠EYL.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

5 0

Answer:

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL) Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

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Tcecarenko [31]

Answer:

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Step-by-step explanation:

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3 years ago

If arc XV = 80° and arc YX = 120°, what is the measure of ?YUV?

kramer

Answer:

The measure of angle YUV is 40°

Step-by-step explanation:

Consider the diagram of this question is attached below,

Where, Tangent line UV and secant XY intersect outside the circle at U,

Since,

$\widehat{XV}+\widehat{XY}+\widehat{VY}=360^{\circ}$

We have,

$\widehat{XV}=80^{\circ}, \widehat{XY}=120^{\circ}$

$\implies 80^{\circ}+120^{\circ}+\widehat{VY}=360^{\circ}$

$200^{\circ}+\widehat{VY}=360^{\circ}$

$\widehat{VY}=360^{\circ}-200^{\circ}=160^{\circ}$

Since, the measure of intercepted angle outside the circle is half of the difference of measure of intercepted arcs,

$\implies m\angle YUV = \frac{\widehat{VY}-\widehat{XV}}{2}$

$=\frac{160^{\circ}-80^{\circ}}{2}$

$=\frac{80^{\circ}}{2}$

$=40^{\circ}$

6 0

4 years ago

!!Time Sensitive 20pts!!

Sati [7]

Note how y changes by a factor of 1/5 each time x increases by 1. Thus, the mult. rate of change here is 1/5.

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4 years ago

Read 2 more answers

Find n 5|6n+15|+2=-43

Ivenika [448]

Answer:

<h2>No solution</h2>

Step-by-step explanation:

$5|6n+15|+2=-43\qquad\text{subtract 2 from both sides}\\\\5|6n+15|+2-2=-43-2\\\\5|6n+15|=-45\qquad\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup^1|6n+15|}{5\!\!\!\!\diagup_1}=\dfrac{-45\!\!\!\!\!\diagup^9}{5\!\!\!\!\diagup_1}\\\\|6n+15|=-9\qquad\bold{FALSE}\to\text{no solution}\\\\\text{because}\ |a|\geq0\ \text{for any real value of}\ a.$

3 0

3 years ago

A right triangle has a hypotenuse of 10 mi. and a leg of 6 mi., what is the length of the other leg?

slava [35]

Answer:

8mi

Step-by-step explanation:

Using Pythagoras theorem

Hypotenuse square = opposite square + adjacent square.

Let the other leg be x

10 square = 6 square + x square

100 = 36 + x square

Collect like terms

X square = 100 -36

X square = 64

Find square root of both sides

X = square root of 64

X =8mi

I hope this was helpful, Please mark as brainliest

7 0

3 years ago