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Assoli18 [71]
3 years ago
15

Find the value of x need answer quick please I tried to make question worth more but I don’t know how :(

Mathematics
2 answers:
Ivan3 years ago
7 0

In the figure we have three parallel lines cut by two transversals

The theorem stares:

If two or more parallel lines are cut by two transversals, then they divide the transversals proportionally.

Applying this theorem we have:

\frac{4}{x} =\frac{6}{5}

To solve for x we cross multiply

6x=20

Dividing both sides by 6 we have:

x=\frac{20}{6} =\frac{10}{3}  =3\frac{1}{3}

The second option x=3\frac{1}{3} is the right answer

Aneli [31]3 years ago
5 0

When parallel lines are cut by transversals, the lengths of the segments of the transversals are proportional.

6/4 = 5/x

6x = 5 * 4

6x = 20

x = 20/6 = 10/3

x = 3 1/3

Answer: B. 3 1/3

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sasho [114]

Answer:

B!

Step-by-step explanation:

4 0
3 years ago
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Amy needs to order a shade for a triangular-shaped window that has a base of 6 feet and a height of 8 feet. What is the area of
Akimi4 [234]

Answer:

24

Step-by-step explanation:

A triangle is a three sided polygon with three edges and three vertices

There are different types of triangles. They include :

  • Right angled triangle - one of the angles measure 90 degrees
  • equilateral triangle - all three sides of the triangle are equal
  • isosceles triangle - two sides of the triangle are equal

Area of a triangle = 1/2 x ( base x height)

1/2 x (6 x 8) = 24 ft²

8 0
2 years ago
You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?
Rasek [7]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}

\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61

5 0
2 years ago
Please help with this
zysi [14]
Crayon and then marker
7 0
3 years ago
Read 2 more answers
Which of the following measures cannot be determined from a box plot?
ad-work [718]
<h3>3 Answers:</h3>
  • B) Mean
  • C) Mean absolute deviation
  • E) Mode

==========================================================  

Explanation:

The box plot, aka "box-and-whisker plot", visually represents five things. These things are:

  • Minimum
  • Q1 = first quartile
  • Median (sometimes referred to as Q2 or second quartile)
  • Q3 = third quartile
  • Maximum

This list of five items is known as the five number summary.

The min is the tip of the left most whisker, assuming there aren't any small outliers. The max is the opposite side, being the tip of the right most whisker (assuming no large outliers). If there are any outliers, then they'll be shown as "island" dots on their own separated from the main box plot. The left and right edges of the box are Q1 and Q3 respectively. The median is the vertical line inside the box. The vertical line does not have to be at the midpoint of the left and right edges of the box. It simply needs to be somewhere in the box.

--------

Since the box plot lets us know the min and max, we can compute the range because

range = max - min

and we can also calculate the interquartile range (IQR) because

IQR = Q3 - Q1

--------

So to summarize so far, the five number summary is visually represented as the box plot. The range and IQR can be computed using items from the five number summary.

We cannot compute the mean because we would need the actual data set of values, rather than the summary data. The same goes for the mean absolute deviation (MAD) and the mode. Since your teacher is looking for things that cannot be determined from a box plot, we'll go for answers B, C and E.

In other words, we rule out choices A, D, and F because we can compute or determine those values from a box plot.

7 0
2 years ago
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