The volume of the shape
We have a cylinder that is cut into two. Its external radius is 5ft, while its internal radius is 4ft.
External radius = internal radius + thickness
![\begin{gathered} \text{External radius = 4ft + 1ft } \\ =\text{ 5ft} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BExternal%20radius%20%3D%204ft%20%2B%201ft%20%7D%20%5C%5C%20%3D%5Ctext%7B%20%205ft%7D%20%5Cend%7Bgathered%7D)
Internal radius = 4ft (given)
Recall that the volume(V) of a full cylinder is:
![V\text{ = }\pi r^2h](https://tex.z-dn.net/?f=V%5Ctext%7B%20%3D%20%7D%5Cpi%20r%5E2h)
Since the cylinder is cut into two, the volume(V) is:
![V\text{ = }\frac{\pi r^2h}{2}](https://tex.z-dn.net/?f=V%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5Cpi%20r%5E2h%7D%7B2%7D)
height (h) = 12ft (given)
The volume of the shape:
Answer:
g=1.5
Step-by-step explanation:
you want to eliminates the 2/5 so you do that by dividing it by itself (since you do the opposite equation) you do this on both side (so do 2/5 divided by itself, and 3/5 divided by 2/5) getting you 1.5 therefore all you have on the left side if this equation is g so g=1.5
18x+9y
9x+y
x+1/9y
2x+4.5y
x+2.25y
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