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Ivanshal [37]
3 years ago
12

Whats 2 12/7 as a whole number? Plz Halp

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

12/7 = 1.7142

2 + 1.7142 rounded to a while number would be 4 or 3.17142

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What is the value of x?<br> 68<br> 4x + 12<br> 17<br> 15<br> 32<br> 8
Marianna [84]

Answer:

k12

Step-by-step explanation:

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I NEED HELP ASAP PLSSS
Triss [41]

Answer:

y = x^2 - 4x - 5

y = (x + 1)(x - 5)

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Someone please help me !
Leni [432]

Answer:

Can't tell if it went through...

1. Shop A = 2x

2. Shop B = 2x - 580

3. Total = Shop A + Shop B

1949 = 2x + 2x - 580

4. Combine like terms

2x + 2x = 4x

1949 = 4x - 580

5. Add 580 to both sides (to remove -580 from right side)

1949 + 580 = 4x - 580 + 580

2529 = 4x

6. Divide both sides by 4 (to get x)

2529 / 4 = 4x / 4

632.25 = x

7. Shop A = 2x

2 * 632.25 = 1264.50

Shop A = 1264.50

8. Shop B = 2x - 580

2 * 632.25 - 580 = 684.50

Shop B = 684.50

Check: Shop A + Shop B = 1949

1264.50 + 684.50 = 1949

Shop A = 1264.50

Shop B = 684.50

Step-by-step explanation:

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3 years ago
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lawyer [7]
Part a: subtract 48-30=18
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3 0
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Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
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