Ask question

Ask question

All categories

3 years ago

12

Two circles of radius 8 are tangent to the graph of

1 answer:

KengaRu [80]3 years ago

5 0

Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle

</span>

You might be interested in

For the order of operations, Group of answer choices Multiplication, division and remainder is performed first Addition and subt

Furkat [3]

Answer: Addition and subtraction is performed after multiplication, division and remainder

Step-by-step explanation:

The correct order of operations is to calculate whatever is in the parenthesis first.

Then calculate multiplication and division depending on which comes first as you move from left to right.

Then addition and subtraction can be performed also depending on which comes first as you move left to right.

8 0

2 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately <u>63.7 ft.</u>

The braking distance at 55 mph, is approximately <u>298.35 ft.</u>

The braking distance at 85 mph, is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0

1 year ago

Which function is the inverse of f(x) = 2x + 3?

lianna [129]

Answer:

y = 1/2x - 3/2

Step-by-step explanation:

The easiest way to find the inverse is to switch x and y and solve for y.

y = 2x + 3

x = 2y + 3 (Switch)

x-3 = 2y (Subtract y from both sides)

x/2 - 3/2 = y (Divide both sides by 2)

8 0

3 years ago

Read 2 more answers

Give answer fast...<br>it's very important for me....<br>then I give you 20 thanks...(◍•ᴗ•◍)❤

Vedmedyk [2.9K]

Answer:

I have the answer

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Represent the situation using an equation. Check your answer with a visual model or numeric method.

Lyrx [107]

Answer:

Step-by-step explanation:

n(30/100)=27

n=100(27)/30

n=90

3 0

2 years ago