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iVinArrow [24]
3 years ago
12

Two circles of radius 8 are tangent to the graph of

Mathematics
1 answer:
KengaRu [80]3 years ago
5 0
 Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle

</span>
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What is the least common multiple of 14, 20, and 15?
Komok [63]

14, 15, 20 | 2

7, 15, 10 | 2

7, 15, 5 | 3

7, 5, 5 | 5

7, 1, 1 | 7

1, 1, 1

Answer: \bf2^{2} × 3 × 5 × 7 = 420

Hope it helped,

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Step-by-step explanation:

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poizon [28]

Well, all we have to do is add, so:

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3 years ago
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Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


5 0
3 years ago
F(x) = <br> 1<br> x<br><br> g(x) = <br> 1<br> x − 1<br> − 1
baherus [9]

Answer:

x=0, x=2

Step-by-step explanation:

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