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pishuonlain [190]
3 years ago
14

2.2.3 + 5.68 + 21.047=

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

22.3 + 5.68 + 21.047= 49.027

2.23 + 5.68 + 21.047= 28.957

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36 rows of 27 trees were planted in the orchard. how many total trees were planted in the orchard ​
kherson [118]

Answer:

972 trees

Step-by-step explanation:

36 times 27

8 0
3 years ago
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I have another one sry out fated meme but i need 1-1 is it 0? or is it -1
Murljashka [212]

Answer:

It is 0

Step-by-step explanation:

6 0
4 years ago
Figure A is a scale image of Figure B.
Sauron [17]

<em>Greetings from Brasil...</em>

According to the statement, one figure is scaled in relation to another, so we can apply similarity to polygons.....

So

BIG/small = BIG/small

or

small/BIG = small/BIG

27/X = 45/35

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7 0
3 years ago
Let f(x) = -5x^6√x + -7/x³√x. What would f’(x) be? If anyone could show me step-by-step, I would greatly appreciate it! I’ve wor
Illusion [34]

Answer:

                                  f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}

or

                                  f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}

Step-by-step explanation:

Rather than solving this question in a more complex method by directly using the product rule and quotient rule, it can first be considered to perform some algebraic manipulation (index laws) to simplify the expression before taking the derivative.

                                       \begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^6\ \sqrt{x}\ +\ \frac{-7}{x^3\ \sqrt{x}}\\\\f\left(x\right)\ =\ -5x^6\cdot x^{\frac{1}{2}}\ +\ \frac{-7}{x^3\cdot x^{\frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{6\ +\ \frac{1}{2}}\ +\ \frac{-7}{x^{3\ +\ \frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ +\ \frac{-7}{x^{\frac{7}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\end{array}

Now, the derivative of the function can be calculated simply by only using the power rule, which yields

                   \begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\\\\f^{\prime}\left(x\right)\ =\ \left(-5\right)\left(\frac{13}{2}\right)\left(x^{\frac{13}{2}\ -\ 1}\right)\ -\ \left(7\right)\left(-\frac{7}{2}\right)\left(x^{-\frac{7}{2}\ -\ 1}\right)\\\\f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}\\\\f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}\end{array}\\\end{large}

8 0
2 years ago
What is the interquartile range if the data set? 5,911,13,16,16,19,21
max2010maxim [7]

Answer:

Step-by-step explanation:

5,9,11,(13,16),16,19,21

the mean(middle number) = (13 + 16) / 2 = 29/2 = 14.5

Q1 = (9 + 11) / 2 = 20/2 = 10

Q3 = (16 + 19) / 2 = 35/2 = 17.5

interquartile range (IQR) = Q3 - Q1 = 17.5 - 10 = 7.5 <==

7 0
3 years ago
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