Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

= x + 0.5 x

= 1.5 x

Therefore the amount of acid in first container $=x \times \frac{30}{100}$ = 0.3 x

The amount of acid in second container $=1.5x \times \frac{50}{100}$ = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount of solution = x+1.5x = 2.5x

The amount of acid in third container is = $\frac{1.05x}{2.5x} \times 100%$ %

= 42%

4 0

4 years ago

CAN YOU ALSO HELP ME WITH THIS: 2x/4 + 3/8 = x/ 16- 3/2

Svetach [21]

Answer: x = − 30 7 Decimal Form : x = − 4. ¯¯¯¯¯¯¯¯¯¯¯¯ 285714 Mixed Number Form : x = − 4 2 7

Step-by-step explanation:

3 0

3 years ago

Citrus farmer who grows mandarin oranges finds that the diameters of mandarin oranges harvested on his farm follow a normal dist

SSSSS [86.1K]

Answer:

6.0520

Step-by-step explanation:

Given that:

Mean = 5.85

Standard deviation = 0.24

Let N denote the 80th percentile.

P(X < N) = 0.8

$P(Z < \dfrac{(N - 5.85)}{0.24}) = 0.8$

Using the Excel formula: = NORM.INV(0.8,5.85,0.24)

The 80th percentile for the diameters of mandarin oranges:

= 6.0520 (to 4 decimal place)

8 0

3 years ago