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Lesechka [4]
3 years ago
12

Camera class help please

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
7 0
D. Drop it is the answer
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Kevin draws a lewis structure for the molecule of ozone, o3. later on that day, he draws another one for a friend to show what h
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<span>The most important part of a lewis structure is that it's number of valence electrons matches the number needed for the atom(s). Because lewis structures are drawn with many "slots" for valence electrons, they can be assigned in a loose order as long as they do not inherently change the shape or number of electrons for the atom. Therefore different lewis structures can be formed, just keep the variables the same.</span>
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3 years ago
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How many grams of water can be produced from 10 moles of hydrogen gas?
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10 moles of H2 reacts with 5 moles of O2 creating 10 moles of water.
Water has the molar mass 18 g/mole
10 · 18g = 180 g 
180 g of water can be produced from 10 moles of hydrogen gas.
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4 years ago
The air above earth’s surface is at different temperatures. What is responsible for this difference in temperature?
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3 0
3 years ago
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Please help appreciate it!!
zysi [14]

Explanation:

Ionization reactions are reactions that involve an electrically neutral atom or molecule be converted into electrically charged atom or molecule (ions).

Ions are recognized by the (⁺) and (⁻) signs.

First Reaction: Ions are formed so this option is correct.

Second Reaction: Ions are formed so this option is correct.

Third Reaction: This option is wrong. No ions are formed.

Fourth Reaction: Ions are formed so this option is correct.

Fifth Reaction: Ions are formed so this option is correct.

8 0
3 years ago
Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the vol
marta [7]

Answer:

V_2=19.23L

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

\frac{V_2}{n_2} =\frac{V_1}{n_1}

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol

Thus, we find:

V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L

Best regards.

6 0
3 years ago
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