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11111nata11111 [884]
3 years ago
9

a high school athlete Department bought 40 soccer uniforms at a cost of $3,000. After soccer season, they returned some of the u

niforms but only received $40 per uniform. What was the difference between what they paid for each uniform and what they got for each return?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

(3,000 / 40) - 40x =

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Slope: 3/4, y-intercept: -1
Amiraneli [1.4K]

Answer:

y = 3/4 x -1

Step-by-step explanation:

The equation for a line with the slope and the intercept is y = mx+b  where m is the slope and b is the y intercept

y = 3/4 x -1


5 0
2 years ago
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Suppose the measure of an angle is 67 degrees what is the measure of its complementary angle
avanturin [10]
Complementary angles are angles whose sum is 90 degrees.

90 - 67 = 23

23 degrees is the measure of its complementary angle.
3 0
3 years ago
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
3 years ago
Solve for b<br> Is it square root 39? <br> Or <br> Square root 89?
cricket20 [7]

Answer:39

Step-by-step explanation:

7 0
3 years ago
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What is the slope intercept form of the equation of 6x+5y=-15
Soloha48 [4]
Slope intercept form is \sf y=mx+b, where 'm' is the slope and 'b' is the y-intercept.

\sf 6x+5y=-15

Subtract 6x to both sides:

\sf 5y=-6x-15

Divide 5 to both sides:

\boxed{\sf y=-\dfrac{6}{5}x-3}
7 0
3 years ago
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