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prohojiy [21]
3 years ago
9

4(2x - 1) = 3x + 6 Solve for x. Show steps with sentences supporting each step.

Mathematics
2 answers:
mr Goodwill [35]3 years ago
5 0

Answer:

x = 2

Step-by-step explanation:

4(2x - 1) = 3x + 6

Simplify

8x - 4 = 3x + 6

Subtract 3x from both sides

8x - 3x - 4 = 3x - 3x + 6

5x - 4 = 6

Add 4 to both sides

5x - 4 + 4 = 6 + 4

5x = 10

Divide both sides by 5

5x/5 = 10/5

x = 2

faust18 [17]3 years ago
5 0

Step-by-step explanation:

4(2x - 1) = 3x + 6

8x-4=3x+6

8x-3x=6+4

5x=10

x=10/5=2

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3x6-2x4 in Bidmas someone please help
insens350 [35]

Answer:

10

Step-by-step explanation:

1. 3 x 6 = 18

2. 2 x 4 = 8

3. 18 - 8 = 10

<em>A. </em>10

8 0
2 years ago
Given that 1ST GRAPH and 2N GRAPH, which theorem or postulate proves ΔPQR 3RD GRAPH ΔRST?
Monica [59]
HL congruence theorem is the answer.

Hope this helps :)
7 0
3 years ago
Factor the following polynomial 9x2 + 21x – 18
solong [7]

Answer:

factors are

21 and x

Step-by-step explanation:

equation 9 × 2 + 21x - 18

terms 9 , 2, 21x, -18

factors 21x = 21 and x

4 0
3 years ago
Read 2 more answers
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
Can someone hel me please
alexdok [17]
1:
10=6
5=3
not sure
2:
triangle=16
circle=27
square=26
3: c
6: .78 per minute
7: they both have the same price one jaut has more ounces
7: they would make 10.56 dollars profit
5 0
1 year ago
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