Question

What constant acceleration is needed to accelerate a baseball from 6 feet/sec to 116 feet/sec in 2 seconds?

Answer 1

Answer:

  d. 55 feet /sec^2

Step-by-step explanation:

Average acceleration is ...

  a = ∆v/∆t = (116 ft/s -6 ft/s)/(2 s)

  = 110/2 ft/s^2 = 55 ft/s^2