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2 years ago

What constant acceleration is needed to accelerate a baseball from 6 feet/sec to 116 feet/sec in 2 seconds?

Mathematics

1 answer:

Vesnalui [34]2 years ago

4 0

Answer:

d. 55 feet /sec^2

Step-by-step explanation:

Average acceleration is ...

a = ∆v/∆t = (116 ft/s -6 ft/s)/(2 s)

= 110/2 ft/s^2 = 55 ft/s^2

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oshua is planning the awards breakfast for the freshman class. The catering company charges a $350 fee for the rental materials,

S_A_V [24]

Firsly remove the $350
$625-$350=$275
Each person is $6,so divide that from $275
275/6=45R5
The remaining $5 cannot be used to pay for another person,so we leave it as extras.
Therfore,45 people were at the the party.

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3 years ago

What's the slope of the line ? And explain please

tia_tia [17]

You take the difference between any two y and divide by the difference in the corresponding x. The number should be the same always for a straight line. That's your slope. A fancy way of writing it is dy/dx

so: (10-2)/(3-1) = 8/2 = 4 (using the first two points)
or: (26-2)/(7-1) = 24/6 = 4 (using the first and the last)

try it out for other combinations. The answer is 4 every time.

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3 years ago

How much is 110 hours in days and hours

eimsori [14]

4 days and 14 hours.

Method I used:

1. Do 110÷24 and you should get <span>4.58333333333. Ignore the numbers after the decimal point, and write down 4 as your number of days.
2. Do 4</span>×24 (you should get 96) and subtract that from 110 (you'll get 14). The difference will be the number of hours.

Hope I helped! <3

5 0

2 years ago

Read 2 more answers

The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?

Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0

2 years ago

Find the value of x. <br> View picture for full problem. Please and thank you!<br> m<2 = 6x + 12.

Karo-lina-s [1.5K]

Answer:

x = 8

Step-by-step explanation:

All the sides are equal. So, it is an equilateral triangle. So, all angles are 60 each

6x + 12 = 60

6x = 60 - 12

6x = 48

x = 48/6

x = 8

4 0

2 years ago