Answer:
the plane's current height above the ocean is 3.42 miles
Step-by-step explanation:
Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.
What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.
For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.
let a = diagonal distance = 10 miles
let the opposite angle to the diagonal distance be A = 90° (right angle)
let the vertical distance = b
let the opposite angle to the vertical distance be B = 20°
Sine rule states that 
∴ 


⇒ b = 3.42 miles
Therefore the plane's current height above the ocean is 3.42 miles
-4x + 2y = -6
2y = 4x - 6
y = 2x - 3....y int = -3 , x int = (3/2,0)
I believe it is going to be : -4x + 2y = -6
700ml=23.6698fl
64-23.6698=40.3302
40.3302fl
Answer:
1) 5/4 or 1 1/4
2) 9/16
Step-by-step explanation:
3/4+1/2: you multiply 1/2 by 2 to get a common denominator then get 2/4, 3+2=5, 5/4 or 1 1/4
1/3+11/48: you multiply 1/3 by 16 to get common denominator & get 16/48, 16+11= 27/48, divide by 3 & get simplest form of 9/16