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lyudmila [28]
3 years ago
7

Te dog’s nap started at 7:14am and ended at 7:57am. How long was the dog’s nap?

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

The answer is 43 minutes I'm pretty sure.

Whitepunk [10]3 years ago
5 0

Answer:

43 mins

Step-by-step explanation: All you have to do is subtract 57 from 14 then you will get your amount of time. And that is all you have to do

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inn [45]
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2 years ago
In the circle below, chord AB passes through the center of circle 0. If the radius OC is perpendicular to chord AB and has lengt
Airida [17]

Answer:

Option (C)

Step-by-step explanation:

In the given circle, AB is a chord passing through the center O.

Therefore,chord AB is a diameter of the circle and OC is the radius.

AO = OB = OC

OC⊥AB, and length of OC = 7 cm

By applying Pythagoras theorem in right ΔBOC,

BC² = OC² + OB²

BC = \sqrt{OC^{2}+OB^{2}}

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Therefore, Option (C) will be the answer.  

7 0
3 years ago
See attached picture, is there a way to enter equations or algebraic symbols?
coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}

(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

(C)

\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

(D)

\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

5 0
1 year ago
Find the volume of the following figure using unit cubes.
krok68 [10]

Answer:

<h2>        64 units³</h2>

Step-by-step explanation:

2 units × 4 units × 8 units = 64 units³

5 0
3 years ago
What is the answer!!! Pls reply!!
Ulleksa [173]
2 11/12 is your answer because 

3-2=1+1=2

and 4/12 - 3/12 = 1/12 + 10/12 = 11/12.
7 0
3 years ago
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