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Arada [10]
3 years ago
9

The Precision Scientific Instrument Company manufactures thermometers that are supposed to give readings of 0°C at the freezing

point of water. Tests on a large sample of these thermometers reveal that at the freezing point of water, some give readings below 0°C (denoted by negative numbers) and some give readings above 0°C (denoted by positive numbers). Assume that the mean reading is 0°C and the standard deviation of the readings is 1.00°C. Also assume that the frequency distribution of errors closely resembles the normal distribution. A thermometer is randomly selected and tested. Find the temperature reading corresponding to the given information.
​If 6.3% of the thermometers are rejected because they have readings that are too high and another 6.3% are rejected because they have readings that are too low, find the two readings that are cutoff values separating the rejected thermometers from the others.


–1.46° , 1.46°


–1.39° , 1.39°


–1.53° , 1.53°


–1.45° , 1.45°
Mathematics
2 answers:
noname [10]3 years ago
4 0

Answer:

School questions are kinda randomly generated but for the most part the answer is mostly B or C

Step-by-step explanation:

B or C

d1i1m1o1n [39]3 years ago
4 0

Answer:

-1.53 , 1.53

Step-by-step explanation:

It is basically asking you to find the percentiles. so for the bottom 6.3% you would type into your calculator 2nd, VARS, invNorm, area: .063, mean: 0, and Standard Deviation: 1 which gives you -1.53.

for the upper 6.3% you have to take 1-.063=.937 to get the upper percentile. now type into your calculator 2nd, VARS, invNorm, area: .937, mean: 0, and Standard Deviation: 1 which gives you 1.53.

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The histogram presents the compressive strengths of a sample of concrete blocks hardened for 28 days.
dusya [7]

Answer:

The question is not complete but I have uploaded the image to complete the question.

The missing rectangle has a relative frequency of 0.15, and this is the same as the height.

Step-by-step explanation:

Let us define what a frequency and relative frequency are

The frequency of a datum is the number of times a given item (datum) appears in the data set.

While the relative frequency is the fraction or proportion of times taken from the whole in which an item/datum occurs.

So, from the image I uploaded, the relative frequency column represents the height of the histogram. Let the height of the missing rectangle be <em>x.</em>

Therefore the heights of the rectangles written from left to right are 0.05, 0.1, 0.15, <em>x, </em>0.25, 0.2, and 0.1.

From the definition of relative frequency, the total sum of relative frequency is 1, if represented as decimals or fractions it can either be expressed in percentage, or decimal (fractions). In this question, it is represented in decimal, and the sum of all the relative frequency is 1.

0.05 + 0.1 + 0.15 + <em>x </em>+ 0.25 + 0.2 + 0.1 = 1 ;

0.85+ <em>x </em>=1

Therefore, <em>x </em>= 1 - 0.85= 0.15

3 0
3 years ago
Baily has been measuring the growth of a flower. It has grown ¾ of an inch each week. It is now 3 inches tall. How many weeks ha
Shkiper50 [21]
Four days long i t will be completed
8 0
2 years ago
Read 2 more answers
In a mixture of​ concrete, there are fourfour lb of cement mix for each pound of gravel. If the mixture contains a total of 2952
Anton [14]

Answer: there are 59059 lbs of gravel.

Step-by-step explanation:

In a mixture of​ concrete, there are four lbs of cement mix for each pound of gravel. This means that eight lbs of cement would be mixed for 2 pounds of gravel and 12 lbs of cement would be mixed for 3 pounds of gravel and 12. Therefore, the constant ratio of cement to gravel is 4:1

The total ratio is 4 + 1 = 5

If the mixture contains a total of 295295 lb of these two​ ingredients, then the number of pounds of gravel that are​ there is

1/5 × 295295 = 59059 lbs

3 0
3 years ago
An insurance company issues life insurance policies in three separate categories: standard,preferred,and ultra- preferred. Of th
slega [8]

Answer:

a) 0.0002

b) 0.0057

c) 0.0364

Step-by-step explanation:

Lets start by stating the probabilities of a person belonging to each policy:

Standard: 0.3

Preferred: 0.5

Ultra- Preferred: 0.2

The probability of person belonging to each policy AND dying in the next year:

Standard: 0.3 x 0.015 = 0.0045

Preferred: 0.5 x 0.002 = 0.001

Ultra- Preferred: 0.2 x 0.001 = 0.0002

a) The probability a ultra - preferred policy holder dies in the next year is 0.001. To find the probability of a person being both a ultra - preferred policy holder AND die in the next year is: 0.001 x 0.2= 0.0002

b)  The probability is given by adding the probabilities calculated before :

0.0045 + 0.001 + 0.0002 = 0.0057

c) We use the results above again. This is 0.0002 / (0.001 + 0.0045). The answer comes out to be 0.0364

6 0
3 years ago
Carla has already written 10 pages of a novel. she plans to write 15 additional pages per month until she is finished. write and
grin007 [14]
Linear Equation: 15m+10=w
15 pages written for every month for 5 months plus the 10 pages she has already written is equal to the total number of pages written in 5 months.
m= number months written. In this case, it is 5 months.
w= number of pages written in 5 months
15(5)+10=w
75+10=w
85 pages written=w
Carla will have written 85 pages in 5 months.
4 0
3 years ago
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